A toy car of mass 0.15kg accelerates from a speed of 10 cm/s to a speed of 15 cm/s. What is the impulse acting on the car?

A graph of the net force F exerted on an object as a function of x position is shown for the object of mass M as it travels a ho

Softa [3030]

The alteration in kinetic energy is $\Delta K = 3Fd$

Clarification:

According to the work-energy principle, the task performed on an object corresponds to the alteration in its kinetic energy. In mathematical terms:

$W=K_f -K_i= \Delta K$

where:

W signifies the work performed on the object

$K_f$ denotes the kinetic energy at the end

$K_i$ indicates the kinetic energy at the start

Furthermore, when the force is exerted in line with the object’s motion, the work done is expressed as:

$W=F\Delta x$

Here,

F represents the force’s magnitude

$\Delta x$ denotes the object’s displacement

In this scenario, the force impacting the object is

F

While the distance moved is the horizontal length traveled, hence

$\Delta x = 3d$

Consequently, the work accomplished is

$W=(F)(3d)=3Fd$

Thus, the alteration in kinetic energy amounts to

$\Delta K = 3Fd$

Learn more about work and kinetic energy:

5 0

3 months ago

A compact car has a maximum acceleration of 4.0 m/s2 when it carries only the driver and has a total mass of 1200 kg . you may w

inna [3103]

<span>Let F represent the maximum thrust produced by the car's motor. Thus, F = ma = 1300 x 3.0 = 3900 N. After adding the load, F stays the same, leading to the equation F = 1700a, which results in a = F/1700 = 3900/1700 = 2.3 m/s².</span>

3 0

4 months ago

Read 2 more answers

An imaginary cubical surface of side L has its edges parallel to the x-, y- and z-axes, one corner at the point x = 0, y = 0, z

Sav [3153]

Refer to the attached file for the solution

7 0

3 months ago