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Aloiza
7 days ago
8

In pea plants being tall (T) is dominant over being short (t). Also in pea plants having green pods (G) is dominant over yellow

pods (g). One plant named George, is heterozygous for height (Tt) and homozygous for yellow pods (gg). George is crossed with another plant named Cici that is homozygous for height (TT) and heterozygous for green pods (Gg). What gametes will the plant named George produce
Biology
1 answer:
lana [2.1K]7 days ago
7 0
The gametes produced by George are 1 Tg: 1 tg.
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Solution: To combat soil erosion, plant vegetation to ensure the roots stabilize the soil.

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Jill is heterozygous for gene A and is going to have a child with Jack, who is homozygous recessive for gene A. Which of the fol
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Answer:

D. Aa

Explanation:

Provided:

Jill (the mother) is heterozygous regarding gene A --------- Jill = Aa

Jack (the father) is homozygous recessive for gene A-------- Jack = aa

Now, when fertilization takes place, we result in:

         A          a

a        Aa        aa

a        Aa        aa

The offspring combinations are (Aa, Aa, aa, aa)

Nondisjunction refers to the failure of homologous chromosomes to separate correctly during cell division. In this scenario, it is stated that the fertilization experienced nondisjunction during meiosis 1, leading both homologous chromosomes to migrate into one daughter cell instead of distributing to two due to improper separation.

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1 month ago
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s2008m [2033]

Answer:

The chance is 0.25 or 25%

Explanation:

To determine the answer, one should utilize a Punnett Square. This tool illustrates the genetic combinations produced from the mating of two parent organisms, allowing visualization of how their alleles combine in offspring. The Punnett Square consists of a grid with eight boxes; one parent's alleles are arranged along the top row, and the other's are positioned down the first column. Each allele from one parent matches with the alleles from the other, filling in the remaining boxes. This results in a genetic probability for the potential offspring's traits.

For the question posed, the cross involving parents who both have Tt (Tt x Tt) alleles is represented below, using the Punnett Square.

          T        t

T        TT       Tt

t        Tt        tt

Within these results, we see that "tt" appears just once among the four possible offspring. Thus, we have a ratio of 1/4, which converts to 0.25, indicating a 25% likelihood that the offspring from this cross will exhibit the "tt" genotype.

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Answer:

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Explanation:

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