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Bad White
1 month ago
10

A female fly is heterozygous for three X-linked genes. The dominant alleles are ABC and the recessive alleles are abc. She is cr

ossed with an abc/Y male. The following progeny phenotypes are produced. These phenotypes are equally divided between male and female flies. Abc 420 aBC 435 abc 55 ABC 60 abC 14 ABc 16 Approximately how many double crossovers progeny would you have expected to see in the total of 1,000?
Biology
1 answer:
-BARSIC- [2.5K]1 month ago
8 0

Response:

(14+16)/1000 *100= 3

Clarification:

Parental combinations tend to be more frequent than other recombinant offspring.

In this scenario, a female fly is heterozygous for three X-linked genes and is mated with a male that carries the abc/Y genotype. When a single crossover happens between genes a and b, as well as between b and c, the instance of double crossing happens at the conjunction of both events.

Offspring resulting from a double crossover are consistently the least numerous, thus in this case, the double crossover variants are represented as abC 14 and ABc 16.

Hence, we anticipate that the quantity of double crossover offspring will be calculated as (14+16)/1000 *100= 3

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