A bug was running along a number line at a speed of 11 units per minute. It never changed its direction. If at 7:15 pm it was at

Question

nignag

2 months ago

13

A bug was running along a number line at a speed of 11 units per minute. It never changed its direction. If at 7:15 pm it was at

the point 100, where could it be at 7:20 pm?

Mathematics

2 answers:

babunello [11.8K] · Answer 1 · 2026-03-29T06:51:16+03:00

babunello [11.8K]2 months ago

8 0

Response:69

Detailed reasoning:69

lawyer [12.5K] · Answer 2 · 2026-03-29T06:49:54+03:00

lawyer [12.5K]2 months ago

3 0

The time from 7:15 to 7:20 is 5 minutes
Since each minute equals 11 units, the total is 5x11=55
Starting from point 100, the new position would be 100+55=155
Final answer: point 155
I hope this is accurate and useful:)