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makvit
9 days ago
7

What is a31 of the arithmetic sequence for which a5=12.4 and a9=22.4

Mathematics
1 answer:
PIT_PIT [9.1K]9 days ago
6 0
In an arithmetic sequence
a₁, a₂, a₃,...,
the n-th term is
a_{n}=a_{1}+(n-1)d
where d = the common difference

Given that a₅ = 12.4,
a₁ + 4d = 12.4           (1)
With a₉ = 22.4,
a₁ + 8d = 22.4          (2)

Subtracting (1) from (2) yields:
a₁ + 8d - (a₁ + 4d) = 22.4 - 12.4
4d = 10
Thus, d = 2.5
From (1),
a₁ = 12.4 - 4*2.5 = 2.4

Consequently,
a₃₁ = 2.4 + 30*2.5 = 77.4
Answer:  a₃₁ = 77.4
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