The steps in writing f(x) = 18x + 3x2 in vertex form are shown, but a value is missing in the last step. Write the function in s

Question

14 days ago

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The steps in writing f(x) = 18x + 3x2 in vertex form are shown, but a value is missing in the last step. Write the function in s

tandard form. f(x) = 3x2 + 18x Factor a out of the first two terms. f(x) = 3(x2 + 6x) Form a perfect square trinomial. f(x) = 3(x2 + 6x + 9) – 3(9) Write the trinomial as a binomial squared. f(x) = 3(x + ______)2 – 27

Mathematics

2 answers:

lawyer [9.2K] · Answer 1 · 2026-03-13T22:14:31+03:00

To determine the vertex form of the given parabola $y=a(x-x_0)^2+y_0$ nearly in standard form $y=ax^2+bx+c,$ the following steps need to be observed:

1. Convert the function into standard form:

$y=3x^2+18x.$

2. Factor out the coefficient from the first two terms:

$y=3(x^2+6x).$

3. Create a perfect square trinomial:

$y=3(x^2+6x+9-9)=3(x^2+6x+9)-3\cdot 9.$

4. Present the trinomial as a binomial squared:

$y=3(x+3)^2-27.$

The vertex coordinates are (-3,-27).

Result: the value that is missing is 3

PIT_PIT [9.1K] · Answer 2 · 2026-03-13T22:14:11+03:00

PIT_PIT [9.1K]14 days ago

5 0

Response:

It appears to be A on e2020

Explanation step-by-step: