PLEASE HELP!! The amount a string stretches varies linearly with the mass applied to the spring, as can be seen in the video. In

Question

2 months ago

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PLEASE HELP!! The amount a string stretches varies linearly with the mass applied to the spring, as can be seen in the video. In

the video, with no additional mass, the hanger was 30.6 cm off the ground. With 150 grams of additional mass, the hanger was 16.2 cm off the ground.
A wooden block stretched the spring so the hanger was 24.8 cm off the ground. Determine the mass of the wooden block, to at least 1 decimal place.

Mathematics

2 answers:

AnnZ [12.3K] · Answer 1 · 2026-03-31T05:52:55+03:00

AnnZ [12.3K]2 months ago

7 0

Hello! The equation is d(m) = k*m, where d(m) equals 0.096 multiplied by m, which is equal to 30.6 - 21.7. Therefore, (30.6 - 21.7)/0.096 yields a result of 92.7 grams. The final answer is 92.7 rounded to one decimal place. Hope this assists you! Best of luck!

Leona [12.6K] · Answer 2 · 2026-03-31T05:55:19+03:00

The mass of the wooden block has been determined to be 60.4 grams. To clarify: Initially, the hanger was positioned 30.6 cm above the ground without any extra mass. We represent the function as f(m) = k*m, where k is a constant. When an additional mass of 150 grams was added, the hanger dropped to 16.2 cm from the ground. Currently, the wooden block has caused the hanger to be at 24.8 cm above the ground, leading us to the conclusion that its mass is 60.4 grams.