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ki77a
9 days ago
6

Marcy has $150 to buy packages of hot dogs and hamburgers for her booth at the carnival. At her local grocery store she found pa

ckages of hot cost $6 and packages of hamburgers cost $20. She has to use her entire budget of $150.
a. Solve the equation for b (burgers)
b. Solve the equation for d (hot dogs)

Mathematics
2 answers:
Svet_ta [12.2K]9 days ago
6 0
Marcy has a total of $150. The price for one hot dog is $6, and one hamburger costs $20. If Marcy were to purchase only hamburgers at cost b, then b = 7 hamburgers. If she buys solely hot dogs at cost d, then. When combining both hamburgers and hot dogs, the equation becomes 6d + 20b ≤ 150, with b > 0, d > 0. This leads to: 3d + 10b ≤ 75, where b represents burgers (X-axis) and d represents hot dogs (Y-axis). Plotting these on a two-dimensional graph shows that the positive integers for x and y solve the equation: 3y + 10x = 75. For example, y = 15 for hamburgers and x = 3 for hot dogs, representing a solution along this line.
lawyer [12K]9 days ago
5 0
6d + 20b = 150 d=5 b=6
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15/28

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