Marcy has $150 to buy packages of hot dogs and hamburgers for her booth at the carnival. At her local grocery store she found pa

A. x + y = 75 B. She dedicates 25 minutes to running and 50 minutes to dancing daily. C. Yes, that's correct.

In 1980, if there were N individuals aged 100 or older, then by 2010, the number grew to N*1.66 for those 100 and above. A straightforward conditional expression can be framed as: If P, then Q, where P represents the hypothesis and Q is the conclusion. We understand that "The count of individuals aged 100 years or older increased by about 66% from 1980 to 2010," meaning that if we had N individuals aged 100 or older in 1980, we will have N*(166%/100%) = N*1.66 in 2010, allowing us to write a conditional statement: If there were N individuals aged 100 years old in 1980, then by 2010, we had N*1.66 individuals who were at least 100 years old.

Answer: 39 cm

Step-by-step explanation:

Let's consider the kite as depicted in the image provided, where TW=5 cm, TX=12 cm, and TZ=4 cm.

First, we need to determine the lengths of the unknown sides to calculate the perimeter, assuming that both the top and bottom parts consist of isosceles triangles.

For the upper segment, we will apply the Pythagorean Theorem to triangle TWZ, with TZ measuring 4 cm and TW being 5 cm. Hence, we must calculate WZ:

By isolating :

For the lower segment, we can apply the Pythagorean Theorem to triangle WZX, where WZ=3 cm and ZX=8 cm. We need to find WX:

Now that the lengths of all sides are identified, the perimeter can be calculated:

The closest option to this calculated value is 39 cm.

Answer:

Detailed explanation:

The sample consists of only 20 individuals, which is insufficient. A minimum of 30 is recommended for a sample size.

Also, the ideal maximum size should not exceed 10% of the total population. Calculating it gives us,

10/100 × 500 = 50

So, this criterion is satisfied.

Thus, the condition not satisfied for inference is that

The sample size must be large enough to presume normality in the distribution of the sample means.

The appropriate choice is

A. II only

½a + ⅔(30) = 50
½a + 20 = 50
½a = 50 - 20
½a = 30
a = 30 × 2
a = 60

Therefore, the solution is 60.

Hope this is useful!