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Liula
1 day ago
9

Write the standard form of the line that contains a slope of -3/8 and passes through the point (5, -4). Include your work in you

r final answer. Type your answer in the box provided or use the upload option to submit your solution.

Mathematics
2 answers:
AnnZ [9K]1 day ago
6 0

Response: 3x+8y+17=0

Detailed explanation:

The formula for a line passing through a designated point (a,b) with slope 'm' is established as follows:

(y-b)=m(x-b)

Given: Slope: m=\dfrac{-3}{8}

Point = (5, -4)

Thus, the equation for the line passing through the point (5, -4) with slope \dfrac{-3}{8} is defined as:

(y-(-4))=\dfrac{-3}{8}(x-5)\\\\\Rightarrow\ 8(y+4)=-3(x-5)\\\\\Rightarrow\ 8y+32=-3x+15\\\\\Rightarrow\ 3x+8y+32-15\\\\\Rightarrow\ 3x+8y+17=0\ \ [\text{In standard form}]

Consequently, the standard form for the line with a slope of \dfrac{-3}{8} passing through (5, -4) is:

3x+8y+17=0

zzz [9K]1 day ago
6 0
The answer with the work has been provided previously.
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