An electrician earns $110 after his first hour of working for a client. His total pay based on the number of hours worked can be

Answer:Tabitha will require 12 teaspoons.

Explanation:

According to the question, Tabitha possesses a teaspoon as her largest volume-measuring tool, and she needs to utilize one-fourth cup of broth.

Knowing that 1 cup equals 16 tablespoons and that there are 3 teaspoons in each tablespoon.

From the given data, we can compute that 16 tablespoons corresponds to (3*16)= 48 teaspoons.

Thus, 1 cup = 48 teaspoons.

Substituting these values, we find that 1/4 cup = 48/4 = 12 teaspoons.

Answer:

The solution to your inquiry can be found below

Step-by-step explanation:

First method

                      20 = 5(-3 + x)                   expanding this equation

                     20 = -15 + 5x                    combine like terms

                     5x = 20 + 15

                     5x = 35                            dividing by 5

                     5x/5 = 35/5

                     x = 7

Second method

                     20/5 = 5/5 (-3 + x)          divide both sides by 5

                     4  = -3 + x                        adding 3 to both sides

                     4 + 3 = -3 + 3 + x            simplifying

                     7 = x

                     

Answer: Ana should produce more fudge, and Leo should produce more toffee.

Step-by-step explanation:

Comparative advantage defined: A person or country has a comparative advantage producing a good if their opportunity cost for it is lower than someone else's.

In this case, Ana and Leo will both benefit if they focus on the product for which they have the lower opportunity cost.

(a) Ana’s production possibilities:

If she spends all her time making fudge: 3 pounds; or toffee: 2 pounds.

Opportunity cost of 1 pound fudge = 2/3 = 0.66 pounds toffee

Opportunity cost of 1 pound toffee = 3/2 = 1.5 pounds fudge

(b) Leo’s production opportunities:

All time making fudge: 4 pounds; or toffee: 5 pounds.

Opportunity cost of 1 pound fudge = 5/4 = 1.25 pounds toffee

Opportunity cost of 1 pound toffee = 4/5 = 0.8 pounds fudge

Since Ana’s opportunity cost for fudge is lower than Leo’s, she should specialize in fudge production.

Conversely, Leo has a lower opportunity cost for toffee, so he should focus on producing toffee.

Important details about isosceles triangle ABC:

• The median CD, which is drawn to the base AB, also acts as an altitude to that base in the isosceles triangle (CD⊥AB). This indicates that triangles ACD and BCD are congruent right triangles, each with hypotenuses AC and BC.
• In isosceles triangle ABC, the sides AB and BC are equal, meaning AC=BC.
• The base angles at AB are equal, m∠A=m∠B=30°.

1. Consider the right triangle ACD. The angle adjacent to side AD is 30°, which dictates that the hypotenuse AC is double the length of the opposite side CD relating to angle A.

AC=2CD.

2. Now, for right triangle BCD, the angle next to side BD is also 30°, so hypotenuse BC is twice the opposite leg CD linked to angle B.

BC=2CD.

3. To calculate the perimeters of triangles ACD, BCD, and ABC:

4. If the total of the perimeters of triangles ACD and BCD is 20 cm greater than the perimeter of triangle ABC, then

5. Given that AC=BC=2CD, the lengths of legs AC and BC of the isosceles triangles are 20 cm.

Answer: 20 cm.

a) The area of a rectangle is calculated by multiplying the length by the width:
   A = l·w

This formula allows us to express the width in terms of area and length. By dividing A by l, we find
   A/l = w

We also recognize that the perimeter of a rectangle is the total length around it.
   P = l + w + l + w
   P = 2(l + w)
We aim to rewrite the perimeter formula to isolate l on one side, using the expression for w derived earlier.
   P = 2(l + A/l)

By substituting the known value for A, we can express p(l) as
   p(l) = 2(l + 25/l)
   p(l) = 2l + 50/l


b) For lengths exceeding widths, we have
   l > w
   l > A/l
   l² > A
   l > √A
   l > √25

This indicates that the domain of p(l) is
   l ∈ (5, ∞)..... meters