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Natasha2012
6 days ago
6

Need help on 4.9.2 project: performance task: the subway stop

Mathematics
1 answer:
tester [3.8K]6 days ago
3 0
You might have better success by searching for answers individually:)
You might be interested in
The perimeter of a rectangle is 202. The length is 26 more than 4 times the width. Find the dimensions
Inessa [3895]

Answer:

P = 2*(26+4y) + 4y

Upon solving for y, we find:

202= 52 +8y +4y

202= 52 +12 y

By substitution, we have:

150 = 12y

Thus, we arrive at:

y = \frac{150}{12}= 12.5

And for x, we determine:

x = 26 +4*12.5 = 76

This gives us a length of 76 and a width of 12.5.

Step-by-step explanation:

We are dealing with a rectangle. The formula for the perimeter is:

P= 2x+2y

Here, x denotes the length and y the width. The following conditions can be established:

x = 26 +4y

Substituting these values yields:

P = 2*(26+4y) + 4y

When we solve for y, we find:

202= 52 +8y +4y

202= 52 +12 y

By substitution, we obtain:

150 = 12y

Thus, we conclude:

y = \frac{150}{12}= 12.5

The length is found to be 76, while the width measures 12.5.

6 0
4 days ago
If Ana devotes all her time to making fudge, she can make 3 pounds of fudge an hour, and if he devotes all her time to making to
lawyer [3979]

Answer: Ana should produce more fudge, and Leo should produce more toffee.

Step-by-step explanation:

Comparative advantage defined: A person or country has a comparative advantage producing a good if their opportunity cost for it is lower than someone else's.

In this case, Ana and Leo will both benefit if they focus on the product for which they have the lower opportunity cost.

(a) Ana’s production possibilities:

If she spends all her time making fudge: 3 pounds; or toffee: 2 pounds.

Opportunity cost of 1 pound fudge = 2/3 = 0.66 pounds toffee

Opportunity cost of 1 pound toffee = 3/2 = 1.5 pounds fudge

(b) Leo’s production opportunities:

All time making fudge: 4 pounds; or toffee: 5 pounds.

Opportunity cost of 1 pound fudge = 5/4 = 1.25 pounds toffee

Opportunity cost of 1 pound toffee = 4/5 = 0.8 pounds fudge

Since Ana’s opportunity cost for fudge is lower than Leo’s, she should specialize in fudge production.

Conversely, Leo has a lower opportunity cost for toffee, so he should focus on producing toffee.

7 0
14 days ago
The line width of a tool used for semiconductor manufacturing is assumed to be normally distributed with a mean of 0.5 micromete
zzz [4002]

Answer:

a. 0.82%

b. 71.11%

c. 0.564 micrometer

Step-by-step explanation:

To find the z value for each measurement, we must calculate and determine the percentage they correspond to, and the difference will give us the percentage between those two statistics.

The equation for z is:

z = (x - m) / (sd)

Here, x is the value being evaluated, m denotes the mean, and sd represents the standard deviation.

a.

For 0.62 copies, we calculate:

z = (0.62 - 0.5) / (0.05)

z = 2.4

This translates to 0.9918.

Therefore, p (x > 0.62) = 1 - 0.9918

p (x > 0.62) =  0.0082 = 0.82%

b.

For 0.47 copies, we have:

z = (0.47 - 0.5) / (0.05)

z = -0.6, which equates to 0.2742.

For 0.63 copies:

z = (0.63 - 0.5) / (0.05)

z = -2.6, which yields 0.9953.

Hence, p (0.47 > x > 0.63) = 0.9953 - 0.2742

p (0.47 > x > 0.63) = 0.7211 = 72.11 %

c.

For x copies, we find:

p = 0.9 corresponds to z = 1.28.

Thus, 1.28 = (x - 0.5) / (0.05)

From which we derive:

x = 1.28*0.05 + 0.5

x = 0.564 micrometer

4 0
13 days ago
Two parallel lines are crossed by a transversal. Parallel lines x and y are cut by transversal w. On line x where it intersects
AnnZ [3868]

Answer:

118.2°

Step-by-step explanation:

Dos líneas paralelas x e y son cortadas por la transversal w (ver el diagrama adjunto).

Se forman 8 ángulos (denominados 1, 2, 3, 4, 5, 6, 7 y 8).

Los ángulos 1 y 6 son ángulos del mismo lado cuando dos líneas paralelas x e y son cortadas por la transversal w.

Dos ángulos del mismo lado son suplementarios (suman 180°). Esto significa

m\angle 1+m\angle 6=180^{\circ}

Dado m\angle 1=61.8^{\circ}, por lo que

m\angle 6=180^{\circ}-61.8^{\circ}=118.2^{\circ}

8 0
4 days ago
Read 2 more answers
Kathleen and Arnob both run from the park entrance along a loop. Kathleen starts walking from the park entrance and gets a 5-mil
zzz [4002]

In this scenario, the first step is to assign variables.

We define:

x: time measured in minutes

y: distance covered.

The equations formulated are as follows:

For Kathleen:

y = (\frac{1}{15}) x + 5

For Arnob:

y = (\frac{2}{15}) x

At the moment Arnob meets Kathleen, we have:

(\frac{1}{15}) x + 5 = (\frac{2}{15}) x

Next, we isolate x.

We now have:

(\frac{2}{15}) x - (\frac{1}{15}) x = 5

(\frac{1}{15}) x = 5\\x = (15) * (5)\\x = 75 min

Answer:

Arnob takes a total of 75 minutes to catch up to Kathleen:

d. 75

5 0
4 days ago
Read 2 more answers
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