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Natali
21 day ago
5

How is shading a grid to show 1 tenth different from shading a grid to show 1 hundredth?

Mathematics
2 answers:
Svet_ta [12.7K]21 day ago
8 0
For shading one tenth, you would shade only 1 out of 10 rectangles, while for one hundredth, you would shade 1 out of 100 rectangles. The corresponding image is provided below.
AnnZ [12.3K]21 day ago
6 0
To illustrate 1 hundredth (or 1%) on a grid consisting of 100 units, shade only 1 unit. In contrast, to illustrate 1 tenth (or 10%), you would shade 10 units. A visual representation of the grid would be helpful for further explanation.
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Find the derivative of the vector function r(t)=ta×(b+tc), where a=⟨2,−3,4⟩, b=⟨−4,5,−1⟩, and c=⟨−2,−1,5⟩.
lawyer [12517]

Answer:

la derivada de la función vectorial dada es = ( -16-22t, 14-36t, -2-16t )

Explicación paso a paso:

datos proporcionados:

función vectorial: r(t) = ta*(b+tc)

a = ( 2,-3.4).   b = (-4,5,-1).  c = ( -2,-1,5)

para determinar la derivada de la función vectorial, se procederá a diferenciar respecto a x; aquí está la solución detallada

7 0
1 month ago
The employees at retail store earn $8.75 per hour. They can earn 1.5 times their hourly wage for every hour they work over 40 in
AnnZ [12381]
At a wage of 8.75 per hour, total earnings for 40 hours would be 350. Calculate overtime at 8.75 times 1.5 which equals 13.13. Then, multiply 13.13 by 12 to get $158. So the total is 350 + 158 = 508, likely around 480 after taxes for the US.
3 0
1 month ago
Llen's score in a video game was changed by −50 points because he missed some targets. He got −10 points for each missed target.
AnnZ [12381]
Llen missed 5 targets, which is due to -50 divided by -10 equaling 5. I hope this clarifies! <3
6 0
18 days ago
the vertex form of a function is g(x) = (x – 3)2 9. how does the graph of g(x) compare to the graph of the function f(x) = x2? g
Inessa [12570]
The vertex of the graph for the function g(x) = (x- 3)^2 + 9 is located 3 units to the right and 9 units upwards compared to the vertex of the function f(x) = x^2.
9 0
1 month ago
Read 2 more answers
What other points are on the line of direct variation through (5, 12)? Check all that apply. (0, 0) (2.5, 6) (3, 10) (7.5, 18) (
Inessa [12570]

It is established that

A correlation between two variables, x and y, demonstrates a direct variation if it can be written in the format y/x=k or y=kx

For this question, we have

the point (5,12) lies on the direct variation line

therefore

Determine the constant of proportionality k

y/x=k-------> substitute ------> k=12/5

The equation is

y=\frac{12}{5}x

Keep in mind that

If a point is located on the direct variation line

then

the point has to fulfill the direct variation equation

we will now validate each point

case A) point (0,0)

x=0\ y=0

Insert the values of x and y into the direct variation equation

0=\frac{12}{5}*0

0=0 -------> is valid

thus

the point (0,0) lies on the direct variation line

case B) point (2.5,6)

x=2.5\ y=6

Insert the values of x and y into the direct variation equation

6=\frac{12}{5}*2.5

6=6 -------> is valid

thus

the point (2.5,6) lies on the direct variation line

case C) point (3,10)

x=3\ y=10

Insert the values of x and y into the direct variation equation

10=\frac{12}{5}*3

10=7.2 -------> is not valid

thus

the point (3,10) does not lie on the direct variation line

case D) point (7.5,18)

x=7.5\ y=18

Insert the values of x and y into the direct variation equation

18=\frac{12}{5}*7.5

18=18 -------> is valid

thus

the point (7.5,18) lies on the direct variation line

case E) point (12.5,24)

x=12.5\ y=24

Insert the values of x and y into the direct variation equation

24=\frac{12}{5}*12.5

18=30 -------> is not valid

thus

the point (12.5,24) does not lie on the direct variation line

case F) point (15,36)

x=15\ y=36

Insert the values of x and y into the direct variation equation

36=\frac{12}{5}*15

36=36 -------> is valid

thus

the point (15,36) lies on the direct variation line

ultimately

the solution is

(0,0)

(2.5,6)

(7.5,18)

(15,36)


5 0
1 month ago
Read 2 more answers
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