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worty
2 months ago
11

A certain species of rabbit can have either black or grey fur. The allele for black fur is dominant over the allele for grey fur

. If a homozygous black rabbit is crossed with a heterozygous black rabbit, what phenotypic ratio will occur in the first generation?
A.
50% black : 50% grey
B.
100% black : 0% grey
C.
75% black : 25% grey
D.
25% black : 75

Biology
2 answers:
-BARSIC- [2.5K]2 months ago
6 0

The correct response is B

Assuming the black fur allele is B and the white fur allele is b, breeding a homozygous black rabbit with a heterozygous black rabbit will lead to the outcomes shown in the punnet square below;

Genotypically, 50% of the offspring will be homozygous dominant, while the other 50% will be heterozygous. However, all offspring will display black fur because the black allele is dominant over the grey allele.

vlada-n [2.5K]2 months ago
4 0

Answer:

B.  100% black: 0% grey

Explanation:

Since the black fur allele (BB) dominates the grey fur allele (bb), the offspring from a cross between a homozygous black rabbit (BB) and a heterozygous black rabbit (Bb) will result in all rabbits exhibiting a black phenotype.

The mating is displayed below:

Parental         BB        x         Bb

F1                BB      BB       Bb         Bb

The genotypic ratio =>  BB: Bb = 1:1 meaning 50% homozygous dominants & 50% heterozygous dominants.

The phenotype will be 100% black rabbits and 0% grey rabbits.

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