Sarah was collecting money for charity. By Sunday night she had collected 55% of her target amount. On Monday she collected anot

The formula modeling this scenario is (-2)(4). The breakdown of the process shows that shifting from 0 to -2 represents -2 units, and similar deductions follow through other steps reaching -8, with a total change of -2 units per step. Thus, the model results in (-2) × 4.

Let’s define the number of nickels as n,

the number of dimes as d, and

the number of quarters as q.

The total quantity of coins is 844.

We can express this as "number of nickels + number of dimes + number of quarters = Total coins.

Thus, we can form an equation from this statement as

n+d+q = 844            ---------------------equation(1).

Additionally, it is given that Emilia possesses as many quarters as dimes.

Consequently, the number of quarters equals the number of dimes.

This leads to another equation:

q = d                          ------------------------equation(2).

It is also stated that there are "twice as many nickels as dimes."

We can create a further equation representing this statement as

n = two times the number of dimes

or n= 2d                -------------------------- equation (3).

Three equations have been established.

Let’s solve this system of three equations using substitution methods.

By substituting q = d and  n= 2d  into equation (1), we obtain

n+d+q = 844      =>

2d +d + d = 844.

Adding up the d's, gives us

4d =844.

Dividing both sides by 4 yields

d = 211.

Hence, the quantity of dimes = 211.

Next, we will determine the number of nickels and quarters.

We know that the number of quarters equals the number of dimes.

Thus, the total count of quarters is 211.

The overall quantity of coins sums to 844.

Hence, the number of nickels = 844 -  (sum of quarters and dimes).= 844 -(211+211) = 844 - 422

= 422.

Therefore,

the total of nickels = 422.

Now, let’s compute the total values of all coins.

A nickel is valued at $0.05

A dime is valued at $0.10

A quarter is valued at $0.25.

The total value = 0.05 *(number of nickels) + 0.10*(number of dimes) + 0.25*(number of quarters).

=[ 0.05* 422 + 0.10 *211 + 0.25*211].

= 21.10 + 21.10 + 52.75.

= 94.95.

So, the total worth of all 844 coins = $94.95.

Emilia saved $94.95.

A(n)=a(1)+(n-1)d=
a(n)=2+(n-1)2=2+2n-2=2n

Answer:

The exact population of Vermont in 2008 could have been around 618,000

Step-by-step explanation:

* Here's how rounding to the nearest ten thousand works:

- Numbers ending with the last four digits between 0001 and 4999 are rounded down to the nearest lower multiple of ten thousand

- Example: 83,525 rounds down to 80,000.

- If the last four digits are 5000 or above, round up to the next higher ten thousand

- Example: 58,988 rounds up to 60,000

* Applying this rule to the problem given:

Since the rounded population is 620,000 to the nearest ten thousand, the actual population could be any value with the last four digits from 0001 to 4999 (like 618,000) or from 5000 upwards (like 624,000).

Therefore, 618,000 might represent the actual population of Vermont in 2008

96 soldiers will remain unassigned and the arrangement will consist of 52 rows.