Answer:
Below is the Python code with suitable comments.
Explanation:
#Input file name acquisition
filename=input('Enter the input file name: ')
#Opening the input file
inputFile = open(filename,"r+")
#Dictionary definition.
list={}
#Read and split file content using a loop
for word in inputFile.read().split():
#Check if the word exists in the file.
if word not in list:
list[word] = 1
#Increment count by 1
else:
list[word] += 1
#Closing the file.
inputFile.close();
#Output a blank line
print();
#Sorting words according to their ASCII values.
for i in sorted(list):
#Display unique words along with their
#frequencies in alphabetical order.
print("{0} {1} ".format(i, list[i]));
Answer:
Refer to the explanation
Explanation:
Number of Mobiles=x1
Number of Workstations=x2
Constraints:
50x1 + 70x2 <= 1,60,000
250x1 + 700x2 <= 12,000,000
x1 >= 0 x2 >= 0
Objective function N(x1, x2) = 7800000000 x1 + 7200000000 x2
Excel formulae:
G17 = D9 * E7 + F9 * G7
G18= D10 * E7 * F10 * G7
G19= E7
G20= G7
G21= I17 * E7 + I18 * G7 (This will yield the Maximum)
And E7 and G7 will be the solution.
Set up your sheet as shown in the diagram and apply the formulas.
Access the tool and select solver. Upon opening the Solver dialog, confirm ‘Assume Linear model’ and ‘assume non-negative’. Click to solve the model and keep the solution.
Response: a file containing audio
Clarification:
Response:
C++ code provided below with suitable annotations
Clarification:
pattern.cpp
#include<iostream>
using namespace std;
void printCross(int n)
{
int i,j,k;
if(n%2) //odd number of lines
{
for(int i=n;i>=1;i--)
{
for(int j=n;j>=1;j--)
{
if(j==i || j==(n-i+1))
cout<<j;
else
cout<<" ";
}
cout<<"\n";
}
}
else //even number of lines
{
for(int i=1;i<=n;i++)
{
for(int j=1;j<=n;j++)
{
if(j==i || j==(n-i+1))
{
cout<<" "<<j<<" ";
}
else
cout<<" ";
}
cout<<"\n";
}
}
void printForwardSlash(int n)
{
if(n%2)
{
for(int i=n;i>=1;i--)
{
for(int j=n;j>=1;j--)
{
if(j==n-i+1)
{
cout<<j;
}
else
cout<<" ";
}
cout<<"\n";
}
}
else
{
for(int i=1;i<=n;i++)
{
for(int j=1;j<=n;j++)
{
if(j==(n-i+1))
{
cout<<j;
}
else
cout<<" ";
}
cout<<"\n";
}
}
}
void printBackwardSlash(int n)
{
if(n%2) // odd number of lines
{
for(int i=n;i>=1;i--)
{
for(int j=n;j>=1;j--)
{
if(j==i)
{
cout<<j;
}
else
cout<<" ";
}
cout<<"\n";
}
}
else //even number of lines
{
for(int i=1;i<=n;i++)
{
for(int j=1;j<=n;j++)
{
if(j==i)
{
cout<<j;
}
else
cout<<" ";
}
cout<<"\n";
}
}
}
int main()
{
int num;
char ch;
cout<<"Create a numberes shape that can be sized."<<endl;
cout<<"Input an integer [1,50] and a character [x,b,f]."<<endl;
cin>>num>>ch;
if(ch=='x' || ch=='X')
printCross(num);
else if(ch=='f' || ch=='F')
printForwardSlash(num);
else if(ch=='b' || ch=='B')
printBackwardSlash(num);
else
cout<<"\nWrong input"<<endl;
return 0;
}
In Python: import random def simulate_visited_area_codes(): area_codes = [] for i in range(51): num = random.randint(200,1000) area_codes.append(num) visited_codes = [289, 657, 786, 540] count = 0 for i in range(51): for j in range(len(visited_codes)): if area_codes[i] == visited_codes[j]: count+=1 return count print("Visited Areas: " + str(simulate_visited_area_codes())) Explanation: Your question appears to lack many details, and therefore I will make some assumptions. These are: The 50 area codes are stored in the area_codes list, which is populated with randomly generated values. The visited area codes are saved in visited_codes list, initially set as [289, 657, 786, 540]. The subsequent program aims to count and explain the necessary steps.
