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mihalych1998
14 days ago
13

Write a statement that defines an ifstream object named inputFile and opens a file named "Friends.txt".

Computers and Technology
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#Write a function called "angry_file_finder" that accepts a #filename as a parameter. The function should open the file, #read i
ivann1987 [1066]

Answer:

I am crafting a Python function:

def angry_file_finder(filename): #function definition, this function takes the file name as input

with open(filename, "r") as read: #the open() function is employed to access the file in read mode

lines = read.readlines() #readlines() yields a list of all lines in the file

for line in lines: #iterates through every line of the file

if not '!' in line: #checks if a line lacks an exclamation mark

return False # returns False if a line does not include an exclamation point

return True # returns true if an exclamation mark is present in the line

print(angry_file_finder("file.txt")) invokes the angry_file_finder function by supplying a text file name to it

Explanation:

The angry_file_finder function accepts a filename as its parameter. It opens this file in read mode utilizing the open() method with "r". Then it reads every line using the readline() function. The loop checks each line for the presence of the "!" character. If any line in the file lacks the "!" character, the function returns false; otherwise, it returns true.

There is a more efficient way to write this function without using the readlines() method.

def angry_file_finder(filename):

with open(filename, "r") as file:

for line in file:

if '!' not in line:

return False

return True

print(angry_file_finder("file.txt"))

The revised method opens the file in reading mode and directly uses a for-loop to traverse through each line to search for the "!" character. In the for-loop, the condition checks if "!" is absent from any line in the text file. If it is missing, the function returns False; otherwise, it returns True. This approach is more efficient for locating a character in a file.

7 0
1 month ago
In cell e5, create a formula using the vlookup function to determine the dog type for teen anna morante based on the program cod
Natasha_Volkova [1026]
Hi! For utilizing the VLOOKUP function, you require the value to search for, the table’s range, and the specific column that has the return value. In your scenario, you provided both the range and the column; however, it’s unclear what value you wish to look up. For this explanation, let’s assume you want to search for the value in cell D5. Feel free to modify it according to your needs.

In syntax form, it will be:
=VLOOKUP(D5,G4:H7,2)
3 0
2 months ago
Read 2 more answers
George and Miguel are considering opening up a shoe store but first need to do market research. Which one of these is NOT part o
Natasha_Volkova [1026]
The answer is D. Based on their research findings, they will draw conclusions and make business decisions.
7 0
3 months ago
Read 2 more answers
Assume a machine during its initial testing phase produces 10 widgets a day. After 10 days of testing (starting on day 11), it b
Harlamova29_29 [1022]

Response:

Python Code:

n = int(input("Days: "))

total = 0

for i in range(1,n+1):

     if i <= 10:

           total += 10

     elif i <= 60:

           total += 40

     elif i <= 99:

           total += 100 - i

print(str(total)+ " widgets")

Clarification:

This line requests user input for the number of days.

n = int(input("Days: "))

This line sets the initial total number of widgets to zero.

total = 0

The subsequent loop calculates total widgets based on the established rules.

for i in range(1,n+1):

     if i <= 10: -> Applies when days are 10 or fewer

           total += 10

     elif i <= 60: -> Applies when days are between 11 and 60

           total += 40

     elif i <= 99: -> Applies when days are under 100

           total += 100 - i

This line outputs the total count.

print(str(total)+ " widgets")

4 0
2 months ago
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