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Dominik
1 month ago
11

The figure shows the design of a greenhouse with a rectangular floor. The front and back sides of the greenhouse are semicircles

with a diameter of w and the roof is half a cylinder. Consider greenhouse A with floor dimensions w=16 feet and l =18 feet.
A concrete slab 4 inches deep will be poured for the floor of greenhouse A. How many cubic feet of concrete are needed for the floor?
Mathematics
1 answer:
tester [12.3K]1 month ago
7 0

9514 1404 393

Answer:

96 cubic feet

Step-by-step explanation:

The volume calculation for the dimensions of 16 ft by 18 ft by 1/3 ft is as follows:

V = LWH

V = (16 ft)(18 ft)(1/3 ft) = 96 ft³

Thus, 96 cubic feet of concrete will be required.

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The steps to derive the quadratic formula are shown below: Step 1 ax2 + bx + c = 0 Step 2 ax2 + bx = − c Step 3 x2 + b over a ti
PIT_PIT [12445]

Answer:

x + \frac{b}{2a} = \frac{+/ - \sqrt{b^2-4ac} }{2a}

Step-by-step explanation:

Step 1:

ax^2+bx+c = 0

Step 2:

ax^2+bx = -c

Step 3:

\frac{ax^2+bx}{a} = \frac{-c}{a}

Step 4:

To complete the square, add \frac{b^2}{4a^2} to both sides.

x^2 + \frac{bx}{a} + \frac{b^2}{4a^2} = \frac{-c}{a} + \frac{b^2}{4a^2}

Step 5:

x^2 + \frac{bx}{a} + \frac{b^2}{4a^2} = \frac{-4ac+b^2}{4a^2}

Step 6:

Taking square roots on both sides.

x + \frac{b}{2a} = \frac{+/ - \sqrt{b^2-4ac} }{2a}

3 0
1 month ago
What’s the x value of PR=9x-31 and QR=43?
AnnZ [12381]

Reducing

9x + -31 = 43

Rearranging the components:

-31 + 9x = 43

Finding the solution

-31 + 9x = 43

Isolating the variable 'x'.

Shift all terms with x to one side,

Add '31' to both sides of the equation.

0 + 31 + 9x = 43 + 31

Summing up similar items:

-31 + 31 = 0

0 + 9x = 43 + 31

9x = 43 + 31

Summing similar items:

43 + 31 = 74

9x = 74

Split each side by '9'

x = 8.222222222

Simplifying

x = 8.222222222

6 0
2 months ago
Read 2 more answers
Minato drove 390 miles. Part of the drive was along local roads, where his average speed was 20 mph, and the rest was along a hi
lawyer [12517]

Answer:

45 millas.

Explicación paso a paso:

Dado que la:

Distancia total recorrida = 390 millas

Tiempo total = 8 horas

Designando la distancia recorrida por la vía local como L

y la distancia recorrida por la carretera como H

Por la vía local,

La Velocidad = distancia/ tiempo

20 = L / T

T = L /20.... (1)

Por la carretera,

Distancia recorrida H = 390 - L

Sea el tiempo = t

La Velocidad = distancia/tiempo

60 = (390 - L)/t

t = ( 390 - L)/60

Pero el tiempo total = T + t

<pEs decir

8 = L/20 + (390 - L)/60

<pEl MCM en el lado derecho sería 60<p8 = ( 3L + 390 - L )/60<pMultiplicamos en cruz

480 = 2L + 390

<pAgrupamos los términos semejantes

2L = 480 - 390

2L = 90

L = 90/2

L = 45 millas.

<pAsí que la distancia que Minato recorrió por vías locales es de 45 millas

4 0
1 month ago
A car’s odometer measures distance to the nearest 0.1 miles. Which is the most appropriate way to report the distance driven usi
lawyer [12517]

Answer:

C. 181.7 miles

6 0
20 days ago
A large bag contains 12/15 pound of granola how many 1/3 pound bags can be filled with this amount of granola how much granola i
PIT_PIT [12445]
To determine the number of bags, we simply compute the quotient, which yields:

(12 / 15 pounds) / (1 / 3 pounds) = 2.4 bags

 

Since bags can't be represented in decimals, only 2 bags can be filled. The remainder is 0.4 which can be expressed as:

0.4 * (1/3) = (2/5) * (1/3) = 2/15 pounds

 

Answer:

<span>2 bags are filled, with 2/15 pounds of granola remaining</span>

4 0
19 days ago
Read 2 more answers
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