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postnew
7 days ago
5

HELP ASAP!!! (25 points and I’ll mark brainliest!!!!)

Mathematics
1 answer:
babunello [3.6K]7 days ago
3 0

Answer:

1. Calculate the average distance for each ball hit.

2. The Interquartile Range should be utilized. This represents the difference between the Upper and Lower Quartiles of the ball distances.

3. The Mean should be applied.

4. The Median is advisable as it effectively measures skewed datasets.

Step-by-step explanation:

FIRST PART.

Raul needs to find the average of the distances covered by the ball on each contact.

This involves totaling the distances the ball traveled during every hit and dividing that sum by the number of hits, which is 10.

SECOND PART

He ought to calculate the Interquartile Range, defined as the difference between the Upper Quartile and Lower Quartile for the distances he hit.

THIRD PART

The mean of the distances for the bounces that remained infield should be computed.

This data reflects the most frequently occurring distance during the 9 infield bounces. Including the outfield bounce would skew the center measures, so the mean would be misleadingly low in comparison to his true performance.

FOURTH PART

Calculating the Median is imperative since it is suitable for datasets with skewness.

This is the central value among all recorded distances.

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The following boxplot shows the typical gas mileage, in miles per gallon, for 20 different car models.
Inessa [3907]

Answer:

E

Step-by-step explanation:

My guess is E, since if you total everything and then divide by 2, it equals 30.

6 0
14 days ago
Mai wants to make an open top box by cutting out corners of a square piece of cardboard and folding up the sides. The cardboard
Inessa [3907]

Answer:

V(x)=(4x^{3}-40x^{2}+100x)\ cm^3

The variable x lies within the interval of all positive real numbers less than 5 cm.

Detailed solution:

Problem statement:

Determine the volume of the open-topped box as a function of the side length x (in centimeters) of the square cutouts.

Refer to the provided diagram for clarity.

Define:

x → length in centimeters of each square cutout side

The volume of the box with open top can be written as:

V=LWH

Given this, we have:

L=(10-2x)\ cm

W=(10-2x)\ cm

H=x)\ cm

By substitution:

V(x)=(10-2x)(10-2x)x\\\\V(x)=(100-40x+4x^{2})x\\\\V(x)=(4x^{3}-40x^{2}+100x)\ cm^3

Determine the domain of x:

Because:

(10-2x) > 0\\10> 2x\\ 5 > x\\x < 5\ cm

Therefore:

Domain is the interval (0,5)

That means all real numbers strictly greater than zero and less than 5 cm are valid for x.

Hence, the volume V as a function of x is:

V(x)=(4x^{3}-40x^{2}+100x)\ cm^3

5 0
15 days ago
Leslie is running for a political office. She wants to poll adults in her district to understand their stances on various issues
tester [3916]
Believe this is accurate.
6 0
6 days ago
The perimeter of a scalene triangle is 14.5 cm. The longest side is twice that of the shortest side. Which equation can be used
babunello [3635]
Let x = 6.2
Define y as half of x: y = 0.5x
Calculate y: y = 0.5 × 6.2 = 3.1
Calculate z by subtracting x and y from 14.5: z = 14.5 - 6.2 - 3.1 = 5.2
Each variable corresponds to a triangle side
8 0
14 days ago
jane lives 1 3/8 miles from the airport. She drove from her house to the airport and back 2 times. How far did Jane drive? Move
Leona [4166]

Response:

5\frac{1}{2}\ mi

Detailed explanation:

We are aware that

1\frac{3}{8}\ mi=\frac{1*8+3}{8}=\frac{11}{8}\ mi

She made the trip between her residence and the airport twice.

Therefore,

Multiply the distance from her house to the airport by 4.

(4)*\frac{11}{8}=\frac{11}{2}=5\frac{1}{2}\ mi

4 0
3 days ago
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