The function below takes two numeric parameters. The first parameter specifies the number of hours a person worked and the secon

Response:

d. RAID 6

Clarification:

RAID is a technological method for data storage that integrates several physical hard drive components into a unified logical structure. Its primary purpose is to ensure both performance and data redundancy.

RAID 0 is focused on data striping, but it lacks redundancy.

RAID 1 enhances performance to nearly double but restricts disk space usage to around 50%.

RAID 5 offers both redundancy and improved performance, though it is constrained by smaller drive sizes.

RAID 6 provides redundancy as well but with a decrease in performance.

RAID 10 boosts both performance and data security.

Hence, RAID 6 is the optimal choice that emphasizes redundancy at the cost of speed.

The code relevant to the problem in question:

import java.util.Scanner;

public class Test {

   public static void main(String[] args) {

       double number;

       double squareRootOfNumber;

       String userInput = null;

       Scanner scanner = new Scanner(System.in);

       System.out.println("Please enter a number: ");

       userInput = scanner.next();

       number = Double.parseDouble(userInput);

       squareRootOfNumber = Math.sqrt(number);

       if (number < 0) {

           throw new ArithmeticException("Cannot compute the square root of a negative number");

       }

       System.out.format("The square root of the entered number is %.2f %n", squareRootOfNumber);

   }

}

The program will output:

Please enter a number:

-90

Exception in thread "main" java.lang.ArithmeticException: Cannot compute the square root of a negative number at com..ans.Test.main(Test.java:18)

Explanation:

The standard Java library function java.lang.Math.sqrt does not throw an ArithmeticException for negative arguments, hence there’s no need to enclose your code in a try/catch block.

Instead, we manually trigger ArithmeticException using the throw keyword:

throw new ArithmeticException("Cannot compute the square root of a negative number");

Question:

The function is_positive should yield True if the supplied number is positive; otherwise, it gives None. Can you fill in the blanks accordingly?

def is_positive(number):

       if  _____ :

           return _____

Answer:

def is_positive(number):

   if (number > 0):

       return True

  else:

       return "None"

---------------------------------------------------------------------------------

Code Test and Sample Output:

print(is_positive(6))

>> True

print(is_positive(-7))

>> None

----------------------------------------------------------------------------------

Explanation:

This segment of code is composed in Python.

To explain it further, let's break down the content of each line;

Line 1: Creates a function identified as is_positive which takes in a variable number.i.e

def is_positive(number):

Line 2: Evaluates if the given number is positive; a number qualifies as positive if it exceeds zero. i.e

if (number > 0):

Line 3: Produces a boolean result of True when the input number is positive. i.e

return True

Line 4: Initiates the else block to be executed in case the input number isn’t positive. i.e

else:

Line 5: Returns the string "None" when the number is not positive. i.e

return "None"

When combined, this results in;

===============================

def is_positive(number):

   if (number > 0):

       return True

   else:

       return "None"

================================

An instance test for the code provided an argument of 6 and -7, resulting in True and None respectively. i.e

print(is_positive(6))   = True

print(is_positive(-7))  = None

Answer:

import random

random.seed(1,10) # Note: seed takes one argument, so this line has an error

a = random.randint(1, 10)

b = random.randint(1, 10)

print("Calculate: " + str(a) + " X " + str(b) + "?")

ans = int(input("Your answer: "))

if ans == a * b:

print("Well done!")

else:

print("That's wrong!")

Explanation: