A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To ac

Question

1 month ago

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A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To ac

count for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are:
1) The year must be divisible by 4

2) If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400

Some example leap years are 1600, 1712, and 2016.

Write a program that takes in a year and determines whether that year is a leap year.

Ex: If the input is 1712, the output is:

1712 is a leap year.
Ex: If the input is 1913, the output is:

1913 is not a leap year.
import java.util.Scanner;

public class LabProgram {
public static void main(String[] args) {
Scanner scnr = new Scanner(System.in);
int inputYear;
boolean isLeapYear;

isLeapYear = false;
inputYear = scnr.nextInt();

/* Type your code here. */
}
}

Computers and Technology

2 answers:

amid [951] · Answer 1 · 2026-02-17T11:04:44+03:00

Answer:

def is_leap_year(year):

if(year % 400 == 0):

return True

elif year % 100 == 0:

return False

elif year%4 == 0:

return True

else:

return False

if __name__ == '__main__':

n = int(input())

if(is_leap_year(n)):

print(n,"is a leap year.")

else:

print(n, "- not a leap year")

Explanation:

Rzqust [1K] · Answer 2 · 2026-02-17T11:05:23+03:00

Answer:

import java.util.Scanner;

public class LabProgram {

public static void main(String[] args) {

Scanner scnr = new Scanner(System.in);

int inputYear;

boolean isLeapYear;

isLeapYear = false;

inputYear = scnr.nextInt();

// A year is considered a leap year if it can be divided evenly by 400,

if (inputYear % 400 == 0)

isLeapYear = true;

// However, if a year can be evenly divided by 100, it is not a leap year

if (inputYear % 100 == 0)

isLeapYear = false;

// If a year can be divided by 4, that year will be a leap year

if (inputYear % 4 == 0)

isLeapYear = true;

if(isLeapYear)

System.out.println(inputYear + " is a leap year.");

else

System.out.println(inputYear + " is not a leap year.");

}

Explanation:

If a year is divisible by 400, then the variable isLeapYear is set to true. If a year is a century, divisibility by 100 means it can't be a leap year. When a year meets the criteria of divisibility by 4, it is considered a leap year.

Finally, check the value of isLeapYear; if true, declare it as a leap year. Otherwise, indicate it is not a leap year.

Output:

1712

1712 is a leap year.