Solve x − 5y = 6 for x.

Answer:

x=9,-1 and

Explanation:

We are given the quadratic equation

, which we then compare with the standard form of a quadratic. The general quadratic is identified as

. From our given equation, it follows that a=1,b=-8,c=-9

. To calculate the discriminant, we insert these values into the formula

. Now, to find the value of x

The formula is

. The resulting equation will be obtained by rewriting the original equation through rearranging 9 to the right side and applying negative signs within brackets to convert the expression into the form of

.

Response:

24.2 (rounded to the nearest tenth)

Detailed breakdown:

The data type involved is ungrouped

standard deviation =√ [∑ (x-μ)² / n]

average (μ)=∑x/n

           =

          =33.3

For the values 5, 5, 6, 12, 13, 26, 37, 49, 51, 56, 56, 84, the x-μ results will be

                   -28.3, -28.3, -27.3, -21.3, -7.3, 3.7, 15.7,17.7, 22.7,22.7,50.7

Calculating (x-μ)² gives: 800.89, 800.89, 745.29, 453.69, 53.29, 13.69, 246.49, 313.29, 515.29, 515.29, 2570.49

Then, ∑ (x-μ)² results in = 7028.59

Thus, standard deviation = √(7028.59 / 12)

                      =24.2

     

How often does 245 fit into 8? none.
into 84? none.
into 843? 3

Thus, the initial digit of the quotient is 3. Multiply 245 by 3 to obtain 735. Subtract this number from 843, resulting in 108. How many times does 245 go into 108?
none. Bring down a zero, creating 1080. How many times does 245 fit into 1080? 4, leaving a remainder of 100. And so forth.

Please attempt to work through this problem independently, manually.

________________
245 / 8439.00
-735
----------------

Can you complete this? Keep in mind that 843-735 equals 108. Now drop down a zero to make 1080. show your work.

6 × 10 × 10 × 10 × 10 = Step-by-step breakdown: The exponent of any number reveals how many times that number is multiplied. It signifies the power applied to a number indicating how often that number is multiplied. Here, 10 is used four times, indicating an exponent of 4 for 10. Therefore, the expression can be represented as:

Given:
Total girls in class = 16.
Total boys in class = 14.
To determine:
The various combinations for selecting one girl and one boy.
Solution:
We have,
Total girls = 16
Total boys = 14
Thus,
The total combinations for selecting one girl from 16 girls = 16.
The total combinations for selecting one boy from 14 boys = 14.
Now, the various ways to select one girl and one boy amount to:
Therefore, the total number of combinations is 224.