Answer:
This phrasing is unusual, but let's attempt to tackle it:
M stands for Molly's weight
A represents Arthur's weight
G signifies Ginny's weight.
We can express the total weight as:
(M + A) + G
or alternatively as:
A + (G + M)
the first configuration illustrates Molly and Arthur's weights combined (hence their weight is presented as a single value), followed by Ginny's weight calculated separately.
The second configuration indicates Arthur's weight on its own, while Ginny and Molly's weights are combined (which is why their total weight appears as a single value)
Answer:
Hence, utilizing linear depreciation gives us 17222.22.
Step-by-step explanation:
The boat's initial value is noted to be $250,000.
The straight-line depreciation method for calculating a boat is as follows:
Cost of the boat is $250,000.
Deep Blue anticipates selling it for $95,000 after 9 years.
Employing the formula, we calculate:
(250000-95000)/9=155000/9=17222.22
Thus, the outcome using linear depreciation is 17222.22.
Response:
The area of the shaded part is 42.50 cm².
Detailed explanation:
Examine the diagram provided.
The circle has a radius of r = 5 cm.
Dimensions of the rectangle are:
l = 11 cm
b = 11 cm.
Calculate the area of the shaded portion as follows:
Area of the shaded region = Area of rectangle - Area of circle
![=[l\times b]-[\pi r^{2}]\\\\=[11\times 11]-[3.14\times 5\times 5]\\\\=121-78.50\\\\=42.50](https://tex.z-dn.net/?f=%3D%5Bl%5Ctimes%20b%5D-%5B%5Cpi%20r%5E%7B2%7D%5D%5C%5C%5C%5C%3D%5B11%5Ctimes%2011%5D-%5B3.14%5Ctimes%205%5Ctimes%205%5D%5C%5C%5C%5C%3D121-78.50%5C%5C%5C%5C%3D42.50)
Consequently, the shaded area totals 42.50 cm².
