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ahrayia
15 days ago
10

Explain what you can tell just by comparing the symbols in a picture graph

Mathematics
2 answers:
AnnZ [12.3K]15 days ago
5 0
In a pictorial graph, icons are utilized to depict the data presented. For instance, if a survey was conducted regarding food preferences at a barbecue, we might incorporate images of a hamburger, a hot dog, and a chicken leg. However, we cannot deduce the quantities involved merely by juxtaposing the icons.
tester [12.3K]15 days ago
5 0
Assume there are two automobile manufacturing companies producing distinct vehicles. The monthly production figures are as follows, Company A: 40, 40, 50, 60, 60, 70, 80, 90, 50, 30, 120, 200; Company B: 20, 30, 40, 50, 60, 80, 80, 100, 100, 120, 140, 180. If 10 cars produced equals the symbol Δ, then for Company A, there will be ΔΔΔΔ for 40, ΔΔΔΔ for 50, ΔΔΔΔΔ for 60, and so on; while for Company B, ΔΔ represents 20, ΔΔΔ for 30, and continues similarly. By analyzing the symbols, a comparison can be made easily to determine which company has a higher production count, especially since symbols simplify our task of representation in the data.
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Answer:

\frac{dV(t)}{dt} = - 1675.38

Step-by-step explanation:

In 2017, the kitchen equipment's value was recorded at $14,550.

V(0)=$14550

Its following value is represented by V(t)=14550e^{-0.158t.

We need to ascertain the rate of value change as of January 1, 2019.

V(t)=14550e^{-0.158t

\frac{dV(t)}{dt} =\frac{d}{dt}14550e^{-0.158t

\frac{dV(t)}{dt} =14550 \frac{d}{dt}e^{-0.158t

\\Let u= -0.158t,\frac{du}{dt}=-0.158

\frac{dV(t)}{dt} =14550 \frac{d}{du}e^u\frac{du}{dt}

\frac{dV(t)}{dt} =14550 X -0.158 e^{-0.158t}=-2298.9e^{-0.158t}

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\frac{dV(t)}{dt} =-2298.9e^{-0.158X2}

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