Mike can stitch 7 shirts in 42 hours. He can stitch 1 shirt in hours, and in 1 hour he can stitch of a shirt.

Response:

a) 8

b) 15

c) 34

Detailed explanation:

Section a) Options for neck-wear

Regular ties count = 3

Bow ties count = 5

Overall ties count = 3 + 5 = 8

Any tie can be selected from these 8 available options. Thus, the options for neck-wear total 8.

Section b)

We now calculate choices for using both regular and bow ties.

Selecting a regular tie is independent of the bow tie selection. According to counting principles, if two events are independent, the total ways to realize both equal the product of their individual possibilities. Thus,[

Number of ways to select both ties = Count of ways to choose each tie

So,

Ways for wearing both types of ties = 3 x 5 = 15 ways

Section c)

Count of shirts = 5

Count of skirts = 4

Count of pants = 3

Count of dresses = 7

Choice options for outfits include:

• Shirt paired with Skirt or Pants
• Or simply a dress

Pants can be chosen in 3 ways. Pairing a skirt or pant provides 9 options.

Reapplying counting rules:

Ways to wear a shirt with a skirt or pant = 3 x 9 = 27

Choices for dresses = 7

Consequently, the total is 27 + 7 = 34 outfit combinations.

Answer:

a. 0.82%

b. 71.11%

c. 0.564 micrometer

Step-by-step explanation:

To find the z value for each measurement, we must calculate and determine the percentage they correspond to, and the difference will give us the percentage between those two statistics.

The equation for z is:

z = (x - m) / (sd)

Here, x is the value being evaluated, m denotes the mean, and sd represents the standard deviation.

a.

For 0.62 copies, we calculate:

z = (0.62 - 0.5) / (0.05)

z = 2.4

This translates to 0.9918.

Therefore, p (x > 0.62) = 1 - 0.9918

p (x > 0.62) =  0.0082 = 0.82%

b.

For 0.47 copies, we have:

z = (0.47 - 0.5) / (0.05)

z = -0.6, which equates to 0.2742.

For 0.63 copies:

z = (0.63 - 0.5) / (0.05)

z = -2.6, which yields 0.9953.

Hence, p (0.47 > x > 0.63) = 0.9953 - 0.2742

p (0.47 > x > 0.63) = 0.7211 = 72.11 %

c.

For x copies, we find:

p = 0.9 corresponds to z = 1.28.

Thus, 1.28 = (x - 0.5) / (0.05)

From which we derive:

x = 1.28*0.05 + 0.5

x = 0.564 micrometer

The answer is C. Explanation: The shirt originally priced at $35 has a discount of 15%. Therefore, the savings amount will be calculated accordingly.

Respuesta:

Leslie determinó que el siguiente sistema de ecuaciones tiene infinitas soluciones. ¿Está en lo correcto?

x=4y-4

2x-8y=-24

A. Sí, Leslie está en lo correcto.

B. No, la solución es (-8,-24)

C. No, la solución es (0,-16)

D. No, el sistema de ecuaciones no tiene solución.

Explicación paso a paso:

debes resolverlo como un par de ecuaciones simultáneas y no hay soluciones

si necesitas una explicación más detallada, vuelve a publicar la pregunta y lo haré con gusto

por favor márcalo como el más útil

Answer:

Step-by-step explanation:

<pGreetings!

a. The variable X represents the height of a Goomba, which follows a normal distribution with a mean of μ= 12 inches and a standard deviation of δ= 6 inches.

To find the probability that a Goomba picked at random has a height between 13 and 15 inches, you express it as:

P(13≤X≤15)

Considering that standard normal probability tables provide cumulative values, you can express this range as the cumulative probability up to 15 minus the cumulative probability up to 13. You'll first need to standardize these variable heights to obtain corresponding Z values:

P(X≤15) - P(X≤13)

P(Z≤(15-12)/6) - P(Z≤(13-12)/6)

P(Z≤0.33) - P(Z≤0.17)= 0.62930 - 0.56749= 0.06181

b. Now we have Y as the variable indicating the height of a Koopa Troopa. This variable also follows a normal distribution, with a mean μ= 15 inches and a standard deviation δ=3 inches.

The query concerns the probability that a Koopa Troopa stands taller than 75% of Goombas.

First step:

You need to determine the height of a randomly chosen Koopa Troopa that exceeds 75% of the Goomba population.

This entails determining the value of X corresponding to the limit below which 75% of the population falls, denoted by:

P(X ≤ b)= 0.75

Step 2:

Search the standard normal distribution for the Z value that has 0.75 beneath it:

Next, you will reverse the standardization to solve for "b"

Z= (b - μ)/δ

b= (Z*δ)+μ

b= (0.674*6)+12

b= 16.044 inches

Step 3:

With the height that identifies a Koopa Troopa taller than 75% of the Goomba population determined, compute the probability of selecting that Koopa Troopa:

P(Y≤16.044)

This time, utilize the Koopa’s average height and standard deviation to find the probability:

P(Z≤(16.044-15)/3)

P(Z≤0.348)= 0.636

The likelihood of randomly selecting a Koopa Troopa that is taller than 75% of Goombas is 63.6%

I hope this information is useful!