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ad-work
12 days ago
5

Find the sum of the integers between 301 and 400 inclusive that are multiples of 4.

Mathematics
2 answers:
AnnZ [9K]12 days ago
5 0
Short Answer: 8800. Step One: Identify the first number greater than 300 that is divisible by 4. While 300 is divisible by 4, it doesn't belong to our series. The subsequent number is 304. Step Two: Calculate the total terms in the progression, where a = 304, L = 400, and d = 4. Applying the formula to find the nth term, we derive n = 25. Step Three: Compute the sum using the AP formula, yielding the sum as 8800.
Leona [9.2K]12 days ago
4 0
First, we need to identify the integers between 301 and 400 that are divisible by 4. The initial number is 304, which is the first multiple of 4 in that range. The sequence formed is 304, 308, 312,...,400, creating an arithmetic progression (AP). To determine how many such integers exist, we utilize the AP formula.
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Answer: The coordinates of point T are (13, -6).

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The midpoint formula states that the midpoint between points (a, b) and (c, d) is ((a + c)/2, (b + d)/2).

Let T be (h, k). According to the problem:

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Solving these equations yields T at (13, -6).

So, the required coordinates for point T are (13, -6).

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1 month ago
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Leon’s height = \frac{19}{4}-\frac{1}{3}

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