The owner of a bakery wants to know whether customers have any preference among 5 different flavors of muffin. A sample of 200 c

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The owner of a bakery wants to know whether customers have any preference among 5 different flavors of muffin. A sample of 200 c

ustomers provided the data below. Use a = 0.01. The table below shows how many people were tested at each location and their stated preferences Flavor Orange Blueberry Chocolate Vanilla Vanilla and Raisins # of customers 30 52 38 36 44 Calculate the chi-square test statistic X 2. Test the claim that the probabilities show no preference.

Mathematics

1 answer:

AnnZ [12.3K] · Answer 1 · 2026-04-05T15:35:48+03:00

Thus, there are five distinct flavors. A group of 180 individuals was surveyed. Accordingly, the null hypothesis suggests no significant difference, with each flavor receiving 180/5 = 36 counts. x^2 = $\sum{\frac{(x_i)^2}{m_i}}-n$ . Here, mi indicates the expected frequency based on the hypothesis, which is 36, n = 180, and xi corresponds to the actual observations. By substituting the known values, we find that x^2 = 9. The level of association is expressed as $\sqrt{X^2}/ \sqrt{N(n-1)}$ . This results in approximately 0.10, which surpasses our threshold.