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Harman
4 days ago
15

An in-ground pond has the shape of a rectangular prism. The pond has a depth of 24 inches and a volume of 72,000 cubic inches. T

he length of the pond is two times its width. Find the length and width of the pond to the nearest tenth.
Mathematics
1 answer:
babunello [11.3K]4 days ago
5 0
Let
denote the length of the pond and <span> signify its width. It's recognized that the pond's volume equals the area of its base multiplied by its depth. In this case, the base area can be computed as volume divided by depth, equating to 72000 in³ divided by 24 in, resulting in an area of 3000 in². Given that the area is expressed as x multiplied by y, we come to equation 1, 3000 = x * y. If we have x = 2y, we substitute this into equation 1, leading to 3000 = (2y) * y, simplifying to 2y² = 3000 and consequently y² = 1500, giving y = 38.7 in. Thus, x = 2y yields x = 2 * 38.7 = 77.4 in. The conclusion is that the pond's length is 77.4 in while its width is 38.7 in. </span>
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