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sashaice
3 days ago
7

The distance d (in miles) you travel in a car is given by the two equations shown, where t is the time (in hours) and g is the n

umber of gallons of gasoline the car uses.Two equations: d=55t and d=20g a. Write an equation that relates G & T b. Solve the equation for G c. You travel for six hours. How many gallons of gasoline does the car use? How far do you travel?
Mathematics
2 answers:
lawyer [12K]3 days ago
4 0
We have the equations d=55t and d=20g. The left sides match, as do the right sides. First, we derive the equation: 55t=20g. Then, we can deduce that g=(55/20)t. If t=6 hours, then g=(55/20) *6 = 165/10=16.5 gallons. The distance can be calculated as d= 55t= 55*6=330 miles, which is also equal to d=20g=20*16.5=330 miles.
AnnZ [11.9K]3 days ago
4 0
The distance d (in miles) is defined by d=55t, where t represents time in hours. Similarly, d=20g where g signifies the gallons of gasoline consumed. To relate g to t, we write the equation accordingly. Solving for g, we find: Hence, upon traveling for six hours, the vehicles utilize 16.5 gallons of gasoline. We can apply the equation to ascertain the travel distance.
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Response:

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Next, by adding and subtracting this 5% from our original number, we can find the minimum and maximum possible values of our final answer in the specified range.

9,460,730,472,580.8 + 473,036,523,629 = 9.933767*10^{12}\\9,460,730,472,580.8 - 473,036,523,629 =8.98769395*10^{12}

We can ascertain that 9*10^{12} fits within the acceptable range, as:

8.9*10^{12} \leq 9*10^{12} \leq 9.9 * 10^{12}

Therefore, our final answer will be:

9*10^{12}km

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6 days ago
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Response: The following comparison is made.

Detailed explanation:

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As such, m_1 < m_2

Thus, the slope of the first climbing structure is less than that of the second.


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I believe the answer would be C, based on your previous statements.
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