The table shows the estimated number of lines of code written by computer programmers per hour when x people are working. A 2-co

∠ROT=160°

∠SOT=100°

Now we calculate ∠SOR as follows: ∠SOR = ∠ROT - ∠SOT

∠SOR = 160° - 100°

∠SOR = 60°

It is stated that the angles ROQ, QOS, and POT all have the same measure.

Thus, ∠SOQ + ∠QOR = 60°

Since ∠SOQ equals ∠QOR, we can express this as:

2∠SOQ = 60°

From which we find ∠SOQ = 60° ÷ 2

∠SOQ = 30°

Also, ∠POT = ∠SOQ = ∠ROQ = 30°

Response:

• Refer to the attached graph

• x₁ ≈ - 2.1

• x₂ ≈ 0.2

Clarification:

To analyze log (−5.6x + 1.3) = −1 − x visually, graph these equations on the same coordinate system:

• Equation 1: y = log (5.6x + 1.3)

• Equation 2: y = - 1 - x

The first equation can be graphed using these characteristics of logarithmic functions:

• Domain: values must be positive ⇒ -5.6x + 1.3 > 0 ⇒ x < 13/56 (≈ 0.23)

• Range: all real values (- ∞, ∞)

• x-intercept:

        log ( -5.6x + 1.3) = 0 ⇒ -5.6x + 1.3 = 1 ⇒ x = 0.3/5.6 ≈ 0.054

• y-intercept:

       x = 0 ⇒ log (0 + 1.3) = log (1.3) ≈ 0.11

• Choose additional values to create a table:

        x            log (-5.6x + 1.3)

        -1           0.8

        -2           1.1

        -3           1.3

• This graph is shown in the attached image: it's represented by the red curve.

Graphing the second equation is simpler as it forms a straight line: y = - 1 - x

• slope, m = - 1 (the coefficient of x)

• y-intercept, b = - 1 (the constant term)

• x-intercept: y = 0 = - 1 - x ⇒ x = - 1

• This graph is indicated by the blue line in the image.

The resolution to the equations corresponds to the points where the two graphs intersect. The graphing method thus allows you to determine the x coordinates of these intersection points. Ordered from smallest to largest, rounded to the nearest tenth, we have:

• x₁ ≈ - 2.1

• x₂ ≈ 0.2

Answer:

Refer to the solution provided.

Step-by-step explanation: