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Aleks04
2 months ago
6

Calculate the amount of heat necessary to raise the temperature of 135.0 g of water from 50.4°F to 85.0°F. The specific heat of

water = 4.184 J/g·°C.
Chemistry
1 answer:
KiRa [2.9K]2 months ago
6 0

We are tasked with determining the heat required to elevate the temperature of water from 85.0 ⁰F to 50.4 ⁰F.

To increase the temperature from 50.4 ⁰F to 85.0 ⁰F, a heat amount of 10.857 kJ is necessary.

The needed heat for the temperature increase can be calculated using the equation H = m×s×(t₂-t₁).

In this equation, H is the heat, s represents specific gravity at 4.184 J/g.⁰C, m is the mass of 135.0 g, t₁ (the initial temperature) is 50.4 ⁰F or 10.222 ⁰C, and t₂ (final temperature) stands at 85.0⁰F or 29.444 ⁰C.

After inputting these values, we find:

H = 135.0 g × 4.184 J/g.⁰C × (29.444 - 10.222) ⁰C

Simplifying gives us H = 10857.354 J or 10.857 kJ.

Thus, to elevate the temperature, 10857.354 J or 10.857 kJ of heat is necessary.

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Anarel [2989]

Although multiple values are given, our focus is on HCl.

<span>We have 215 mL (0.215 L) of 0.300 M HCl fully consumed in the reaction. It's important to recall that the number of moles is found by multiplying volume by molarity:</span>

 

moles = 0.215 L × 0.300 M

<span>moles = 0.0645 moles of HCl</span>

4 0
4 months ago
65g of nitric acid are produced in a reaction. 2.5g of platinum are added to the reaction vessel at the start of the reaction to
alisha [2963]

Answer:

2.5 g of platinum

Explanation:

A catalyst is a substance added to a reaction to enhance the reaction speed. It does not undergo any change during the reaction, meaning it remains unchanged after the reaction concludes. The role of a catalyst is to provide an alternative pathway for the reaction by reducing the activation energy required. Therefore, a catalyzed reaction occurs more rapidly and requires less energy compared to an uncatalyzed one.

Since catalysts do not get involved in reactions and retain their mass post-reaction, the amount of platinum will stay the same (2.5g). The mass can only alter if a substance participates in the chemical process. Thus, this is the response.

6 0
3 months ago
How many molecules are in 13.5g of sulfur dioxide, so2?
alisha [2963]
Answer: The number of sulfur dioxide molecules present is 1.27·10²³.
Calculating: m(SO₂) equals 13.5 g.
Using the formula n(SO₂) = m(SO₂) ÷ M(SO₂).
This gives n(SO₂) = 13.5 g ÷ 64 g/mol.
Resulting in n(SO₂) = 0.21 mol.
Subsequently, N(SO₂) = n(SO₂) ·Na.
Therefore, N(SO₂) = 0.21 mol · 6.022·10²³ 1/mol.
Ultimately, N(SO₂) equals 1.27·10²³.
Where n represents amount of substance.
M refers to molar mass.
Na is Avogadro's number.
5 0
3 months ago
Why are salt and sugar both able to dissolve in water, even though the solutes have different types of chemical bonding?
lorasvet [2795]

Result:

Ions interact with hydrogen that has a partially positive charge, facilitating the dissolution of salt in water. On the other hand, sugar is a molecular compound connected by covalent bonds. In a polar covalent bond, the sharing of electrons is uneven

Clarification:

5 0
2 months ago
Los automóviles actuales tienen “parachoques de 5 mi/h (8 km/h)” diseñados para comprimirse y rebotar elásticamente sin ningún d
KiRa [2933]

Response: k = 23045 N/m

Clarification:

To determine the spring constant, one must consider the maximum elastic potential energy that the spring can withstand. The kinetic energy of the vehicle should equal at minimum the elastic potential energy of the spring when it is fully compressed. Hence, we express it as:

K=U\\\\\frac{1}{2}Mv^2=\frac{1}{2}kx^2    (1)

M: mass of the vehicle = 1050 kg

k: spring constant =?

v: car speed = 8 km/h

x: maximum spring compression = 1.5 cm = 0.015m

You need to resolve equation (1) for k. Beforehand, convert the speed v to meters per second:

v=8\frac{km}{h}*\frac{1000m}{1km}*\frac{1h}{3600s}=2.222\frac{m}{s}

k=\frac{Mv^2}{x^2}=\frac{(1050kg)(2.222m/s)^2}{(0.015m)^2}=23045\frac{N}{m}

The spring constant calculates to 23045 N/m

3 0
3 months ago
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