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miv72
12 days ago
11

Marie saved $3,000 dollars last year. She saved $600 in the month of January. What percent of the money she saved last year was

saved during the month of January?
Mathematics
2 answers:
tester [12.3K]12 days ago
5 0
In January, 20% of the total savings were achieved. To find this percentage, first determine the difference (increase) between the two amounts you’re scrutinizing. The increase is calculated as New Number - Original Number. Next, divide this increase by the original figure and then multiply by 100 for the percentage increase.
Svet_ta [12.7K]12 days ago
3 0
Hello there!:) To answer your question, 20% of the total savings from last year was saved during January.
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The fish population of Lake Collins is decreasing at a rate of 3% per year. In 2004 there were about 1,300 fish. Write an expone
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In this scenario, we have a function of the following form: A: initial amount, b: rate of decrease, x: time in years. Plugging in the values results in an exponential decay function suitable for this situation: y = 1300 * (0.97) ^ x. The estimated fish population in 2010 is then calculated to be approximately 1083.
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25 days ago
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Axline Computers manufactures personal computers at two plants, one in Texas and the other in Hawaii. The Texas plant has 40 emp
Zina [12379]

Answer:

a) The likelihood that none of the sampled employees are from the Hawaii plant is 1.74%.

b) The chance that exactly 1 employee from the sample is found working in the Hawaii plant is 8.70%.

c) There is an 89.56% chance that 2 or more employees in the sample are from the Hawaii plant.

d) The probability that 9 employees from the sample are working at the Texas plant is 8.70%.

Step-by-step explanation:

Each employee has two potential employment locations: either Texas or Hawaii. Thus, the binomial probability distribution can be utilized to solve this scenario.

Binomial probability distribution

This distribution defines the probability of achieving exactly x successes in n trials where there are only two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

Here, C_{n,x} denotes the number of ways to choose x objects from a set of n, represented by the subsequent formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of success occurring.

In this context, we know:

The sample comprises 10 employees, therefore n = 10.

a. Calculate the probability that none of the sampled employees are from the Hawaii plant (to 4 decimals)?

Given that 20 out of 60 employees are based in Hawaii:

p = \frac{20}{60} = 0.333

We aim to find P(X = 0).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{10,0}.(0.333)^{0}.(0.667)^{10} = 0.0174

Thus, the likelihood that none in the sample are from Hawaii stands at 1.74%.

b. Calculate the probability that 1 employee from the sample is from the Hawaii plant?

This is represented as P(X = 1).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{10,1}.(0.333)^{1}.(0.667)^{9} = 0.0870

Therefore, there is an 8.70% possibility that 1 employee in the sample comes from Hawaii.

c. Calculate the probability that 2 or more employees in the sample are from the Hawaii plant?

We can observe two scenarios: either fewer than 2 employees are from Hawaii or 2 and beyond. The combined probabilities equal decimal 1. So:

P(X < 2) + P(X \geq 2) = 1

We seek to find P(X \geq 2).

P(X \geq 2) = 1 - P(X < 2)

From problems a and b, we possess values for both probabilities.

P(X < 2) = P(X = 0) + P(X = 1) = 0.0174 + 0.0870 = 0.1044

P(X \geq 2) = 1 - P(X < 2) = 1 - 0.1044 = 0.8956

Accordingly, the chance that 2 or more employees in this sample operate at the Hawaii plant is 89.56%.

d. Calculate the likelihood that 9 employees in the sample are working at the Texas plant?

This corresponds to the probability found in part b for 1 employee working in Hawaii.

Consequently, there is an 8.70% chance that 9 employees belong to the Texas plant.

6 0
1 month ago
"There are 3 teams of 18 employees working today. Company policy says that we need to have 1 supervisor for every 8 employees on
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They require six supervisors.
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2 months ago
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What is the 1000th root of the expression 5(^10^10)
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Solution:

feet

Detailed explanation:

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27 days ago
A ship anchored in a port has a ladder which hangs over the side. The length of the ladder is 200cm, the distance between each r
Leona [12618]

Response:

The answer to the inquiry is 8 hours.

Step-by-step breakdown:

Information

Ladder length = 200 cm

Distance between rungs = 20 cm

Tide rise rate = 10 cm/h

Fifth rung =?

Procedure

1.- Determine the total height the tide must reach

Height = 20 cm x 4

                 = 80 cm   as the first rung is touching the water.

2.- Calculate the time needed

Rate = distance / time

-Solve for time

Time = distance / rate

-Substitute values

Time = 80 cm / 10 cm/h

-Final outcome

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