Melissa has three different positive integers. She adds their reciprocals together and gets a sum of $1$. What is the product of

Question

1 month ago

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Melissa has three different positive integers. She adds their reciprocals together and gets a sum of $1$. What is the product of

her integers? Melissa has three different positive integers. She adds their reciprocals together and gets a sum of $1$. What is the product of her integers?

Mathematics

2 answers:

zzz [12.3K] · Answer 1 · 2026-04-06T08:28:28+03:00

Response:

36

Detailed explanation:

Let the three positive integers be x, y, and z. Therefore,

1/x + 1/y + 1/z = 1

Assuming x = 2.

Then 1/x = ½ and we find that 1/y + 1/z = 1/2

Divide the second portion (1/y + 1/z) into three parts.

3/6 = 1/6 + (1/6 +1/6)

Combine two of the fractions.

1/2 = 1/6 + 2/6

1/2 = 1/6 + 1/3

1/2 + 1/3 + 1/6 = 1

The integers deduced are 2, 3, and 6.

2 × 3 × 6 = 36

Consequently, the product of Melissa’s integers is 36.

Svet_ta [12.7K] · Answer 2 · 2026-04-06T08:28:54+03:00

Svet_ta [12.7K]1 month ago

4 0

Given the three integers are $a,b,c$ , we arrive at

$\dfrac1a+\dfrac1b+\dfrac1c=1$

We can merge the fractions on the left side:

$\dfrac{bc}{abc}+\dfrac{ac}{abc}+\dfrac{ab}{abc}=\dfrac{bc+ac+ab}{abc}=1$

$\implies abc=bc+ac+ab$