First, we determine the percentage increase for the tax.
Initial amount = 25×9 = 225 ⇒ The 9 signifies 9 lots of thousands representing the house's value.
New amount = 28×9 = 252
Tax increase = 252 - 225 = 27
Percentage increase = (27÷225) ×100 = 12%
Therefore, the yearly rent should rise by 12%
Monthly rent is $60
Yearly rent = 60×12 = $720
With a 12% increase = 720×1.12 = 806.4 ⇒ Here, 1.12 is the multiplier derived from 100%+12%=112%=1.12
Monthly rent becomes 806.4÷12 = $67.20, resulting in an additional $7.20 each month.
Answer:
Step-by-step explanation:
It was noted that a music streaming platform modified its format to highlight previously unreleased tracks from emerging artists. The site manager is now aiming to assess whether the daily unique listener count has changed.
The hypothesis is set
(A two-tailed test for mean difference)
The test statistic is calculated, and the p-value turns out to be 0.0743
Assuming a significance level of 5%, we observe that p-value = 0.0743>0.05
Thus, we accept the null hypothesis.
i.e. there is no statistically significant alteration in the average number of daily unique listeners
The p-value serves as an indicator of the extremity of the observed data. If p is lower than alpha, we thus reject H0; otherwise, we accept it.
<span>Determine the configuration of columns and rows for the rectangular arrangement of 120 cupcakes.
=> There must be an even number of rows and an odd number of columns.
=> 120 = 2 x 2 x 2 x 15
=> 120 = 8 x 15
=> 120 = 120
Consequently, the glee club should organize the cupcakes in 8 rows and 15 columns.
This totals up to 120 cupcakes altogether.
</span>
The likelihood she will miss on her first attempt is 52.17%.
Answer:
Given that the frog jumps every 10 seconds
(using digits from a random number table)
- It requires 7 jumps with 2 in the reverse direction (either left or right) for the frog to get off the board in 60 seconds.
- Alternatively, 3 jumps in the same direction will also lead to the frog being off the board.
- Furthermore, it would take 5 jumps with one in the opposite direction within the time limit of 60 seconds to leave the board.
Step-by-step explanation:
A frog positioned right at the center of a 5ft long board is 2.5 ft away from either edge.
Every 10 seconds, the frog jumps left or right.
If the frog's jumps are LLRLRL, it will remain on the board at the leftmost square.
If it jumps as LLRLL, it will jump off the board after fifty seconds.
Given that the frog jumps every 10 seconds
(using digits from a random number table)
- It requires 7 jumps with 2 in reverse direction (either left or right) for the frog to get off the board in 60 seconds.
- Alternatively, 3 jumps in the same direction will also lead to the frog being off the board.
- Furthermore, it would take 5 jumps with one in the opposite direction within the time limit of 60 seconds to leave the board.
