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Tpy6a
10 days ago
15

Patricia wishes to have a rectangular-shaped garden in her backyard. she has 82 ft of fencing material with which to enclose her

garden. letting x denote the width of the garden, find a function f in the variable x giving the area of the garden. what is its domain?
Mathematics
1 answer:
tester [12.3K]10 days ago
7 0
width = x perimeter = 80 or 2(x + l) = 80. Therefore, l = length = 40 - x, leading to the area = x(40 - x), which cannot equal zero. Thus, the condition is x(40 - x) > 0, establishing the domain as 0.
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Which fraction lies between 0.70 and 0.75 on number line?
tester [12383]

Answer:

Please refer to the attachment I have provided below.

It contains the analysis of your query and should assist you in visualizing it.

I hope this is helpful.

8 0
1 month ago
Tags are placed to the left leg and right leg of a bear in a forest. Let A1 be the event that the left leg tag is lost and the e
babunello [11817]

Answer:

0.75 = 75% chance that only one tag is lost, provided at least one tag is lost

Step-by-step explanation:

Independent events:

If A and B are independent events, then:

P(A \cap B) = P(A)*P(B)

Conditional probability:

P(B|A) = \frac{P(A \cap B)}{P(A)}

Here

P(B|A) refers to the probability of event B occurring, given that event A has occurred.

P(A \cap B) is the probability of both A and B occurring together.

P(A) is the probability of event A occurring.

In this scenario:

Event A: At least one tag is missing

Event B: Only one tag is missing.

Each tag has a 40% likelihood of being lost, which is equal to 0.4.

Probability of at least one tag missing:

The events can be considered as either no tags are missing or at least one is. Their probabilities sum to 1. Thus

p + P(A) = 1

p is the probability that none are lost. Each tag has a 60% = 0.6 chance of not being lost, and since they are independent,

p = 0.6*0.6 = 0.36

Then

P(A) = 1 - p = 1 - 0.36 = 0.64

Intersection:

The intersection of at least one lost (A) and exactly one lost (B) is precisely one lost.

Then

Probability of at least one lost:

The first being lost (0.4 chance) and the second not lost (0.6 chance)

Or

The first not being lost (0.6 chance) and the second lost (0.4 chance)

So

P(A \cap B) = 0.4*0.6 + 0.6*0.4 = 0.48

Calculate the probability that exactly one tag is lost, given that at least one tag is lost (round to two decimal places).

P(B|A) = \frac{0.48}{0.64} = 0.75

0.75 = 75% likelihood that precisely one tag is lost, assuming at least one tag is lost

8 0
24 days ago
$0.60 bottle of iced tea marked up to $1.35
zzz [12365]
The result is 0.81 because you must multiply 0.60 by 1.35 to get 0.81. Then divide 0.81 by 0.60.
6 0
1 month ago
Read 2 more answers
Suppose that a student is randomly selected from a large high school. The probability that the student is a senior is 0.22. The
lawyer [12517]

Answer: La probabilidad que necesitamos es 0.16.

Step-by-step explanation:

Se nos proporciona que

La probabilidad de que el estudiante sea un senior = 0.22

La probabilidad de que el estudiante tenga una licencia de conducir = 0.30

La probabilidad de que el estudiante sea un senior o tenga una licencia de conducir = 0.36

Buscamos la probabilidad de que el estudiante sea un senior y tenga licencia de conducir.

Según la pregunta,

P(S\cap D)=P(S)+P(D)-P(S\cup D)\\\\P(S\cap D)=0.22+0.30-0.36\\\\P(S\cap D)=0.16

Por lo tanto, la probabilidad que necesitamos es 0.16.

3 0
1 month ago
4/9 divided by what equals 12?<br> :)
Inessa [12570]

Answer:

To solve (4/9)/x = 12, multiply both sides by x to get (4/9) = 12x. Then, divide both sides by 12. The answer is 27.

I hope this is helpful!

4 0
29 days ago
Read 2 more answers
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