Answer:
Using a scale of 2" means "will take the original and enlarge it to twice its size".
Thus, the resulting photocopy will be double the dimensions of the original.
Step-by-step explanation:
Answer: OPTION B
Step-by-step explanation:
The red graph depicts the fundamental form of a quadratic function (the most basic version), with its vertex located at the origin.
The function g(x) results from moving the parent function 2 units to the right and 1 unit upwards.
As a consequence, considering this, the transformation takes the following structure:

The horizontal displacement is dictated by the value of h, while the vertical shift is determined by k.
<pThus, the resulting function is:

The diagram below illustrates the issue at hand.
Question 1:
The maximum area of the pool equals half the area of the circle.
To calculate the area of the circle: Area = πr², with r being half of the diameter.
Thus, Area of circle = π(60)² = 11309.73355 square feet.
Therefore, the area representing half the circle amounts to 11309.73355/2 = 5654.866... ≈ 5654.87 square feet (rounded to 2 decimal places).
Question b:
To find the pool's area, we take the circle's area and subtract the triangle's area.
The area of the circle is 11309.73 square feet.
For the triangle's area calculation: 1/2 × (60×103.92) = 3117.6 square feet.
The area of the pool thus operates as 11309.73 - 3117.6 = 7922.13 square feet.
Calculating the pool's volume: 7922.13 × 4 = 31688.52 cubic feet.
Note: Information related to the fish tank is unavailable, so the above calculation focuses solely on the entire pool's volume.
You might have better success by searching for answers individually:)
Answer:
The cost for a 2,000 square foot house is 
Detailed explanation:
Recall that if two variables x and y vary directly, the relationship can be written as
or
.
Define:
x as the house area in square feet
y as the price of the house
Given point (1500, 300000)
Calculate proportionality constant k:

Insert values:

The direct variation equation is:

For x = 2000:
Calculate y:
Replace x in equation:

