Calculate cos theta to two decimal places. A. 0.69 B. 1.38 C. -0.07 D. 0.77

A) The independent variable in this scenario is the quantity of books purchased. C) The overall cost for the year hinges on the number of books obtained. E) The output of this function is the total yearly cost.

x2 – 6x + 9  is the answer

If the clock loses 0.1 hours every day, it will take 120 days to lose a total of 12 hours. Counting 120 days from May 17 leads to September 14.

Answer:

1) E(-3, -4), F(1, -3), G(3, -6), and H(1, -6)   reflects across the x-axis

2) E(-3, -1), F(1, -2), G(3, 1), and H(1, 1)     translates 5 units downward

3) E(3, 4), F(-1, 3), G(-3, 6), and H(-1, 6)    reflects across the y-axis

4) E(4, 4), F(8, 3), G(10, 6), and H(8, 6)    translates 7 units to the right

Step-by-step explanation:

The vertices of quadrilateral ABCD are A(-3, 4), B(1, 3), C(3, 6), and D(1, 6).

1) E(-3, -4), F(1, -3), G(3, -6), and H(1, -6)

   A(-3, 4), B(1, 3), C(3, 6), and D(1, 6)

In this instance, the vertices share the same x-coordinates while their y-coordinates are opposites, indicating a reflection across the x-axis.

2) E(-3, -1), F(1, -2), G(3, 1), and H(1, 1)

   A(-3, 4), B(1, 3), C(3, 6), and D(1, 6)

In this case, the x-coordinates of the vertices remain constant, while the y-coordinates of EFGH are reduced by 5 units, indicative of a downward translation of 5 units.

3) E(3, 4), F(-1, 3), G(-3, 6), and H(-1, 6)

   A(-3, 4), B(1, 3), C(3, 6), and D(1, 6)

Here, the vertices share the same y-coordinates while the x-coordinates are opposites, representing a reflection across the y-axis.

4) E(4, 4), F(8, 3), G(10, 6), and H(8, 6)

   A(-3, 4), B(1, 3), C(3, 6), and D(1, 6)

For this case, the y-coordinates for EFGH remain the same while the x-coordinates have increased by 7 units, showing a rightward translation of 7 units.

Answer:

The value of v that minimizes E is v = 3u/2.

Step-by-step explanation:

The given function is;

E(v) = av³L/(v-u)

Applying the quotient rule yields;

dE/dv = [(v-u)•3av²L - av³L(1)]/(v - u)²

By expanding and setting it to zero, we obtain;

[3av³L - 3av²uL - av³L]/(v - u)² = 0

Resulting in;

(2av³L - 3av²uL)/(v-u)² = 0

Multiplying both sides by (v-u)² gives;

(2av³L - 3av²uL) = 0

This means that 2av³L = 3av²uL

Upon simplifying, we have;

2v = 3u.

Thus, v = 3u/2.