Strlen("seven"); what is the output?

Answer:

//This method takes a parameter called myString of type String

public static boolean isEmailAddress (String myString){

//verifying if the @ character exists in the string

if (myString.indexOf("@")!= -1) {

  //ensuring that only a single instance of @ appears in the string

   if (myString.indexOf("@") == myString.lastIndexOf("@")) {

   //confirming absence of space characters

  if (myString.indexOf(" ") == -1) {

    //checking for the absence of newline characters in the string

    if (myString.indexOf("\n") == -1) {

      //checking for absence of tab characters in the string

      if (myString.indexOf("\t") == -1) {

          return true;

      }

    }

  }

}

}

 return false;

}

Explanation:

The method takes a string presumed to be an email address and verifies whether it is valid, returning true if it is valid and false otherwise. The method checks the following conditions:

->The presence of the "@" character

->Only one occurrence of "@" exists in the string

->No spaces present

->No newline characters present

->No tab characters present

Returning true only if all these conditions are met.

Answer:

Explanation:

When removing items from a dictionary, always specify the key in quotation marks.

For example: del country_capital['Prussia']

Failing to place it in quotes will cause the interpreter to view Prussia as a variable, resulting in an error saying that Prussia is not defined.

Code:

user_input=input("") #taking input from user

entries=user_input.split(',')    

country_capital=dict(pair.split(':') for pair in entries) #creating the dictionary from user input

del country_capital['Prussia'] #removing Prussia; failure to include quotes results in an error

print('Prussia deleted?', end=' ')

if 'Prussia' in country_capital: #verifying the presence of Prussia in the dictionary

print('No.')

else:

print('Yes.')

print ('Spain deleted?', end=' ')    

if 'Spain' in country_capital: #checking if Spain is present in the dictionary

print('No.')

else:

print('Yes.')

print ('Togo deleted?', end=' ') #verifying the existence of Togo in country_capital

if 'Togo' in country_capital:

print('No.')

else:

print('Yes.')

Explanation:

Answer:

Refer to the explanation.

Explanation:

We will organize the plaintext into a 4 x 4 matrix (a rectangular array of symbols, numbers, or expressions arranged in columns and rows, in this case, a 4 × 4 configuration with four rows and four columns.) as detailed in the step-by-step explanation below.