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Cerrena
1 month ago
12

For quality control​ purposes, a company that manufactures sim chips for​ cell/smart phones routinely takes samples from its pro

duction process. Since it is important that these chips are nearly fault​ free, one inspection check involves using microscopic equipment to count the number of imperfections on each chip. Suppose the average number of imperfections per 1000 sim chips is 3. What is the probability that a sample this size​ (1000 chips) has 2​ imperfections? (Round to four decimal places.) Group of answer choices
Mathematics
1 answer:
babunello [11.8K]1 month ago
7 0
The likelihood of a sample of this size having 2 imperfections stands at 22.42%. Step-by-step breakdown: Each chip can either be imperfect or perfect. Thus, this scenario can be evaluated using concepts from binomial probability distribution. The binomial probability measures the chance of achieving exactly x successes in n repeated trials, where there are only two possible outcomes. Here, a success signifies an imperfect chip. Given that there are on average 3 imperfections for every 1000 sim chips, we can assess the probability of observing 2 imperfections in a sample of 1000 chips. We want P(X = 2). Consequently, there is a 22.42% probability that a sample of this size has 2 imperfections.
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Which formula can be used to describe the sequence? -2/3,-4,-24,-144...
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The formula that describes the sequence is a_{n}=\frac{-2}{3}(6)^{n-1}

Step-by-step explanation:

The nth-term formula for a geometric sequence is a_{n}=a(r)^{n-1}, where

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∵ The sequence is \frac{-2}{3}, -4, -24, -144,.......

∵ The first term is \frac{-2}{3}

∵ The second term is -4

∴ \frac{-4}{\frac{-2}{3}}=6

∵ The third term is -24

∴ \frac{-24}{-4}=6

∵ The fourth term is -144

∴ \frac{-144}{-24}=6

∵  \frac{a_{2}}{a_{1}} = \frac{a_{3}}{a_{2}} =  \frac{a_{4}}{a_{3}} = 6

∴ There is a consistent ratio between two consecutive terms

∴ The sequence qualifies as a geometric sequence

∵ The formula for the nth term of the geometric sequence is a_{n}=a(r)^{n-1}

∵ a = \frac{-2}{3}

∵ r = 6

∴ The equation for the sequence is a_{n}=\frac{-2}{3}(6)^{n-1}

The formula that can be employed to outline the sequence is a_{n}=\frac{-2}{3}(6)^{n-1}

Learn more:

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