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ale4655
14 days ago
7

If a polynomial function f(x) has roots 0, 4, and 3 + StartRoot 11 EndRoot, what must also be a root of f(x)? 3 + i StartRoot 11

EndRoot Negative 3 + i StartRoot 11 EndRoot 3 minus StartRoot 11 EndRoot Negative 3 minus StartRoot 11 EndRoot
Mathematics
2 answers:
Svet_ta [12.7K]14 days ago
7 0

Answer:

C. 3 - the square root of 11

Step-by-step explanation:

edge 2020

AnnZ [12.3K]14 days ago
4 0

Answer:

3 − √11

Step-by-step explanation:

Any radical roots must exist in conjugate pairs for polynomials with rational coefficients. To discover the conjugate, simply change the sign of the radical.

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\dfrac{\binom91\binom{38}0}{\binom{47}1}=\dfrac9{47}

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) We throw 9 identical balls into 7 bins. How many different ways are there to distribute these 9 balls among the 7 bins such th
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1 month ago
A study1 conducted in July 2015 examines smartphone ownership by US adults. A random sample of 2001 people were surveyed, and th
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Answer:

a) Null hypothesis:p_{1} = p_{2}    

Alternative hypothesis:p_{1} \neq p_{2}  

b) z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}   (1)  

Where \hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{688+671}{989+1012}=0.679  

c) z=\frac{0.696-0.663}{\sqrt{0.679(1-0.679)(\frac{1}{989}+\frac{1}{1012})}}=1.58    

d) In this scenario, we notice that \hat p_1 > \hat p_2 thus the conclusion for this case would indicate

Step-by-step explanation:

Information provided

X_{1}=688 denote the number of men possessing smartphones  

X_{2}=671 signify the number of women possessing smartphones

n_{1}=989 group of men sampled

n_{2}=1012 group of women sampled

p_{1}=\frac{688}{989}=0.696 symbolize the proportion of men with smartphones

p_{2}=\frac{671}{1012}=0.663 symbolize the proportion of women with smartphones

\hat p denote the pooled estimate of p

z would denote the test statistic

p_v signify the value

Part a

The objective is to evaluate if there is a disparity in smartphone ownership between men and women; the hypothesis statements would be:  

Null hypothesis:p_{1} = p_{2}    

Alternative hypothesis:p_{1} \neq p_{2}    

Part b

The statistic relevant to this case is expressed as:

z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}   (1)  

Where \hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{688+671}{989+1012}=0.679  

Part c

By substituting the provided information, we find:

z=\frac{0.696-0.663}{\sqrt{0.679(1-0.679)(\frac{1}{989}+\frac{1}{1012})}}=1.58    

Part d

In this instance, it is evident that \hat p_1 > \hat p_2 thus the conclusion for this case would seem

4 0
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Tiffany is solving an equation where both sides are quadratic expressions. She sets each quadratic equation equal to y and graph
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Answer:

Step-by-step explanation:

The graph can take on three forms as displayed in the figure.

(a) having no intersections

(b) having a single point of intersection (tangency)

(c) having two points of intersection.

Consequently, the maximum number of intersections that these graphs can yield is 2, as illustrated in figure (c).

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Translate and solve: fourteen less than n is greater than 98.
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The solution to the equation is 75.
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