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allochka39001
1 month ago
12

Suppose we are playing draw poker. we are dealt (from a well-shuffled deck) five cards, which contain four spades and another ca

rd of a different suit. we decide to discard the card of a different suit and draw one card from the remaining cards to complete a flush in spades (all five cards spades). determine the probability of completing the flush.
Mathematics
1 answer:
Leona [12.6K]1 month ago
4 0
Assuming we start with a full standard deck of 52 and then draw 4 spades along with 1 card from a different suit, that leaves us with 47 cards still in the deck. We are hoping to draw another spade from these remaining cards. Initially, there were 13 spades, but after drawing five cards, 9 spades remain in the deck. The likelihood of pulling one of these 9 spades from the 47 cards is

\dfrac{\binom91\binom{38}0}{\binom{47}1}=\dfrac9{47}

In other words, we want to get any 1 of the available 9 spades while avoiding any of the other 38 non-spades, and we're drawing just a single card from the 47 cards total.
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Given that Ray E B bisects ∠CEA, which statements must be true? Select three options. m∠CEA = 90° m∠CEF = m∠CEA + m∠BEF m∠CEB =
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Attached is the question in consideration.

m\angle CEA =90 \ (deg)

m\angle BEF=135\ (deg)

\angle CEF forms a straight line.

\angle AEF depicts a right triangle.

The options 1,4,5,6 represent the correct answers.

Step-by-step explanation:

⇒ Given that \ ray\ AE  is ⊥FEC it constitutes a right triangle, leading to m\angle CEA =90\ (deg).

⇒ The measure for \angle BEF =135\ (deg) equals \angle BEF =\angle AEB +\angle AEF = (45+90)=135\ (deg) as \angle AEB bisects \angle AEC, implying that \angle AEB is half of \angle AEC, thus  \angle AEB = 45\ (deg).

⇒\angle CEF represents a straight line, as the angle measures across it yield 180\ (deg).

⇒ The angle measure for \angle AEF = 90\ (deg) is derived from the linear pair concept.

Since \angle CEA + \angle AEF = 180\ (deg), inserting the values of  m\angle CEA =90\ (deg) leads to \angle AEF = 90\ (deg).

The other two options are incorrect as:

  • m\angle CEF=m\angle CEA + m\angle BEF = (90+135)=225

       it surpasses 180\ (deg) while \angle CEF is a               

      straight line.

  • Also, m\angle CEB=2(m\angle CEA) is inaccurate.

     As \angle CEA = 90\ (deg) and \angle CEB=45\ (deg)

Thus, we have a total 4 valid answers.

The confirmed options are 1,4,5,6.

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2 months ago
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15/28

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There are 28 participants total, with 15 being male, resulting in a fraction of 15/28

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