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joja
14 days ago
13

Two concentric circles with radii of 19 and 29 units bound a shaded region. A third circle will be drawn with area equal to that

of the shaded area. What must the radius of the third circle be? Express your answer in simplest radical form.
Mathematics
1 answer:
zzz [12.3K]14 days ago
4 0
The expression is 4*sqrt(30). Work Shown: Let's define circles P and Q with P representing the area of the circle with a radius of 19 and Q for a radius of 29. By using A = π*r², P calculates to 361π and Q to 841π. The resultant shaded area between circles P and Q is R = Q - P, which amounts to 480π. To ascertain the radius of a new circle S that would equal this area, we simplify R = 480π to find r = sqrt(480) leading us to r = 4*sqrt(30).
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Explain why the following expression is false. |x| < -4
Zina [12379]

Step-by-step explanation:

When a negative number is placed within a modulus function, the result will be positive. For instance, |-3| equals 3, |-6| equals 6, and |5| equals 5, etc.

A modulus function, expressed as |x|, is always positive unless x is zero, in which case it equals zero.

Consequently, |x| cannot be less than -4 because |x| is always non-negative. Thus, the statement is inaccurate.

8 0
1 month ago
The curvature of the Tacoma Narrows Bridge in
tester [12383]

Response:

The width of the arch measures 105 meters

Detailed explanation:

The function that describes the width of the arch is

f(x) = -0.016(x - 52.5)² + 45

where x denotes the horizontal distance from the left end of the arch or the width at its base

f(x) indicates the vertical height of the arch

According to the given quadratic equation, the vertex coordinates of the parabola are (52.5, 45).

The vertex coordinates indicate that

the arch's height is 45 meters

and half the horizontal span from the left end is 52.5 meters

Therefore, the bridge's total width is calculated as 2 times the half span from the left side, which is 2 × 52.5

resulting in 105 meters

Consequently, the bridge's width is 105 meters.

4 0
1 month ago
The difference of two supplementary angles is 88 degrees. Find the measures of the angles.
Zina [12379]
The values of the two supplementary angles are 89 and 1.

To arrive at this, we set the angles as A and B.

We understand that A=B+88 and A+B=90 degrees. Solving this gives A as 89 and B as 1.

8 0
1 month ago
Read 2 more answers
What is a3 in an arithmetic sequence in which a10=41 and a15=61
zzz [12365]
\bf \begin{array}{llll}
term&value\\
-----&-----\\
a_{10}&41\\
a_{11}&41+d\\
a_{12}&(41+d)+d\\
&41+2d\\
a_{13}&(41+2d)+d\\
&41+3d\\
a_{14}&(41+3d)+d\\
&41+4d\\
a_{15}&(41+4d)+d\\
&41+5d=61
\end{array}
\\\\\\
41+5d=61\implies 5d=20\implies d=\cfrac{20}{5}\implies \boxed{d=4}\\\\
-------------------------------\\\\

\bf n^{th}\textit{ term of an arithmetic sequence}\\\\
a_n=a_1+(n-1)d\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
d=\textit{common difference}\\
----------\\
d=4\\
n=10\\
a_{10}=41
\end{cases}
\\\\\\
41=a_1+(10-1)4\implies 41=a_1+36\implies \boxed{5=a_1}

therefore

\bf n^{th}\textit{ term of an arithmetic sequence}\\\\
a_n=a_1+(n-1)d\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
d=\textit{common difference}\\
----------\\
d=4\\
n=3\\
a_{1}=5
\end{cases}
\\\\\\
a_3=a_1+(3-1)4\implies a_3=5+(3-1)4

and you are probably aware of the amount.
8 0
22 days ago
Read 2 more answers
Ralph has budgeted $175 for entertainment. He uses this money to go out on dates for $35 or to go out with his friends for $15.
AnnZ [12381]
If Ralph allocated $180 rather than the intended $175 for entertainment, he spent $35 for each date and let's denote "x" as the number of dates he attended. He also spent $15 when going out with friends, where "y" represents his outings with friends.

The accurate equation is "B" which is 35x + 15y = 180.
8 0
1 month ago
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