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Mumz
1 month ago
12

A veterinarian does research on the causes of enteroliths, stones that develop in the colon of horses. She suspects that feeding

alfalfa might be a cause. To investigate that suspicion, she selects five horses that are known to have enteroliths and compares the number of flakes of alfalfa they have eaten over a month with the number of flakes eaten by five horses free of enteroliths. If she calculates a two-sample confidence interval by hand for the difference in the mean number of flakes fed to horses with and without enteroliths the degrees of freedom she should use are:
10.
8.
4.
5.
Mathematics
1 answer:
PIT_PIT [12.4K]1 month ago
8 0

Answer: 8

Step-by-step explanation:

The degrees of freedom for the t-distribution used while testing the difference between two population means can be calculated using the formula:

df= n_1+n_2-2

, where n_1 represents the size of the first sample and

n_1 indicates the size of the second sample.

In this case,

the veterinarian selects five horses that have previously been diagnosed with enteroliths and assesses their monthly intake of alfalfa flakes against that of five horses without enteroliths.

This means we consider n_1=5 and n_2=5

To derive a two-sample confidence interval manually for the average flakes difference between those horses with and without enteroliths, the degrees of freedom required would thus be

df= 5+5-2=8

Consequently, the final answer is 8.

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Answer:

Step-by-step explanation:

I concluded the answer is.25 because it makes sense and I was correct.

4 0
2 months ago
Problem 5 (4+4+4=12) We roll two fair 6-sided dice. Each one of the 36 possible outcomes is assumed to be equally likely. 1) Fin
tester [12383]
1 2 3 Step-by-step explanation: Generally, during the roll of two fair 6-sided dice, the doubles result in (1, 1), (2, 2), (3, 3), (4, 4), (5, 5), (6, 6). Therefore, the total for doubles is N = 6. The outcome of rolling two fair 6-sided dice yields n = 36. Thus, the probability of rolling doubles (matching numbers on both dice) is calculated mathematically. When rolling two fair dice, outcomes that sum to 4 or less are (1, 1), (1, 2), (1, 3), (2, 1), (2, 2), (3, 1). Observing this, we see two doubles present. Consequently, the conditional probability of rolling doubles is represented mathematically. Lastly, when rolling the two fair dice, outcomes that show different numbers result in L = 30, while outcomes where at least one die shows a 1 give W = 10. Hence, the conditional probability of having at least one die show a 1 is presented mathematically.
3 0
2 months ago
Upgrading a certain software package requires installation of 68 new files. Files are installed consecutively. The installation
lawyer [12517]

Answer:

The chance of completing the entire package installation in under 12 minutes is 0.1271.

Step-by-step explanation:

We define X as a normal distribution representing the time taken in seconds to install the software. According to the Central Limit Theorem, X is approximately normal, where the mean is 15 and variance is 15, giving a standard deviation of √15 = 3.873.

To find the probability of the total installation lasting less than 12 minutes, which equals 720 seconds, each installation should average under 720/68 = 10.5882 seconds. Thus, we seek the probability that X is less than 10.5882. To do this, we will apply W, the standard deviation value of X, calculated via the formula provided.

Utilizing \phi, we reference the cumulative distribution function of the standard normal variable W, with values found in the attached file.

P(X < 10.5882) = P(\frac{X-15}{3.873} < \frac{10.5882-15}{3.873}) = P(W < -1,14)

Given the symmetry of the standard normal distribution density function, we ascertain \phi(-1.14) = 1-\phi(1.14) = 1-0.8729 = 0.1271.

Consequently, the probability that the installation process for the entire package is completed within 12 minutes is 0.1271.

Download pdf
7 0
2 months ago
(03.02 MC)
Leona [12618]

Answer: refer to the image

Step-by-step explanation:

5 0
1 month ago
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