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igor_vitrenko
3 months ago
7

​A factory manufactures tennis balls. Each tennis ball is stamped with the number ​1, 2, 3, or 4. The table shown below lists th

e percent of tennis balls stamped with each ​number. What is the probability that a tennis ball selected at random is stamped ​with an even number? ​​ 1/35% 2/30% 3/20% 4/15%
Mathematics
1 answer:
PIT_PIT [12.4K]3 months ago
4 0

Answer:

Step-by-step explanation:

I concluded the answer is.25 because it makes sense and I was correct.

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In the diagram below DE is parallel to XY. What is the value of y?
zzz [12365]

It should be 94, I hope this provides assistance

7 0
3 months ago
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The base of a right pyramid with apex V is a square ABCD of side 10cm. The length of each slant edge is 15cm. Calculate:
PIT_PIT [12445]

Response:

  a. height of the pyramid: 5√7 cm

  b. overall area: (100 +200√2) cm²

  c. volume: (500/3)√7 cm³

Step-by-step explanation:

b) Each triangular face is an isosceles triangle with a base measuring 10 cm and a side length of 15 cm. That side length serves as the hypotenuse of the right triangle formed when an altitude is drawn. The altitude length can be calculated using the Pythagorean theorem as...

  h = √(15² -5²) = √200 = 10√2... cm

The lateral area equals the combined area of the four triangular faces, each one having this altitude and a base of 10 cm

  LA = 4 × (1/2)bh = 2bh

  LA = 2(10 cm)(10√2 cm) = 200√2 cm²

Additionally, the area of the square base is calculated as...

  A = s² = (10 cm)² = 100 cm²

Thus, the total surface area of the pyramid can be expressed as...

  A + LA = (100 +200√2) cm².... overall surface area

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a)  The altitudes of opposite triangular faces along with a line drawn across the center of the base form another isosceles triangle. The height of this triangle corresponds to the pyramid's height. This height can also be derived with the Pythagorean theorem.

The altitude of the face acts as the hypotenuse of the right triangle, with half the base width being one side. The other side equates to the pyramid's height.

  height = √((10√2)² -5²) = √175 = 5√7

The pyramid's height is 5√7 cm.

__

c) The volume is determined using the formula...

  V = (1/3)Bh

where B represents the base area (100 cm²) determined earlier, and h stands for the height (5√7 cm) calculated in section (a).

  V = (1/3)(100 cm²)(5√7 cm) = (500/3)√7 cm³.... pyramid volume

6 0
1 month ago
Which number can each term of the equation be multiplied by to eliminate the fractions before solving? m – negative StartFractio
zzz [12365]

Answer: To remove fractions prior to solving, each term in the equation must be multiplied by 4.

Step-by-step explanation:

Consider the given expression:

-\frac{3}{4}m-\frac{1}{2}=2+\frac{1}{4}m

It is essential to simplify this before attempting to solve it.

Since the denominators differ, identifying the Least Common Denominator (LCD) is necessary.

Break down the denominators into their prime components:

4=2*2=2^2\\2=2

Select 2^2, as it possesses the greatest exponent. Thus:

LCD=2^2=4

Ultimately, to remove the fractions before solving, multiply both sides by 4:

(4)(-\frac{3}{4}m)-(4)(\frac{1}{2})=(4)(2)+(4)(\frac{1}{4}m)\\\\-3m-2=8+m

7 0
3 months ago
Given that Ray E B bisects ∠CEA, which statements must be true? Select three options. m∠CEA = 90° m∠CEF = m∠CEA + m∠BEF m∠CEB =
tester [12383]

Answer:

Attached is the question in consideration.

m\angle CEA =90 \ (deg)

m\angle BEF=135\ (deg)

\angle CEF forms a straight line.

\angle AEF depicts a right triangle.

The options 1,4,5,6 represent the correct answers.

Step-by-step explanation:

⇒ Given that \ ray\ AE  is ⊥FEC it constitutes a right triangle, leading to m\angle CEA =90\ (deg).

⇒ The measure for \angle BEF =135\ (deg) equals \angle BEF =\angle AEB +\angle AEF = (45+90)=135\ (deg) as \angle AEB bisects \angle AEC, implying that \angle AEB is half of \angle AEC, thus  \angle AEB = 45\ (deg).

⇒\angle CEF represents a straight line, as the angle measures across it yield 180\ (deg).

⇒ The angle measure for \angle AEF = 90\ (deg) is derived from the linear pair concept.

Since \angle CEA + \angle AEF = 180\ (deg), inserting the values of  m\angle CEA =90\ (deg) leads to \angle AEF = 90\ (deg).

The other two options are incorrect as:

  • m\angle CEF=m\angle CEA + m\angle BEF = (90+135)=225

       it surpasses 180\ (deg) while \angle CEF is a               

      straight line.

  • Also, m\angle CEB=2(m\angle CEA) is inaccurate.

     As \angle CEA = 90\ (deg) and \angle CEB=45\ (deg)

Thus, we have a total 4 valid answers.

The confirmed options are 1,4,5,6.

5 0
2 months ago
Read 2 more answers
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