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ryzh
8 days ago
8

The idle time for taxi drivers in a day are normally distributed with an unknown population mean and standard deviation. If a ra

ndom sample of 23 taxi drivers is taken and results in a sample mean of 172 minutes and sample standard deviation of 16 minutes, find a 98% confidence interval estimate for the population mean using the Student's t-distribution.
Mathematics
1 answer:
Svet_ta [12.7K]8 days ago
3 0

Answer:

172-2.51\frac{16}{\sqrt{23}}=163.626    

172+2.51\frac{16}{\sqrt{23}}=180.374

Hence, in this case, the 98% confidence interval would be (163.626;180.374)    

Step-by-step breakdown:

Previous concepts

A confidence interval represents a range that is likely to encompass a population value within a specific confidence level, typically expressed as a percentage whereby a population mean falls between an upper and lower limit.

The margin of errorindicates the span of values surrounding the sample statistic in a confidence interval.

A normal distributionillustrates a probability distribution that is symmetrical around the mean, signifying that values near the mean occur more frequently than those farther away from it.

\bar X=172 denote the sample mean

\mu population mean (the variable of interest)

s=16 signifies the sample standard deviation

n=23 represents the sample size  

The solution to the query

The equation for the confidence interval of the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

To determine the critical value t_{\alpha/2}, we first need to calculate the degrees of freedom, which is expressed as:

df=n-1=23-1=22

Since the confidence level is 0.98 or 98%, we find the value of \alpha=0.02 and \alpha/2 =0.01 using tools like Excel or a calculator, where the Excel command would be: "=-T.INV(0.01,22)". This yields t_{\alpha/2}=2.51

Having all components ready, we can substitute into formula (1):

172-2.51\frac{16}{\sqrt{23}}=163.626    

172+2.51\frac{16}{\sqrt{23}}=180.374

Thus, for this case, the 98% confidence interval will be (163.626;180.374)    

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Julia owns a coffee shop. She experimented with mixing City Roast Colombian coffee that costs $7.80 per pound with French Roast
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Answer:

8 lb of French Roast and 12 lb of City Roast coffee

Step-by-step explanation:

In this scenario, we identify two variables: the weight of City Roast coffee (denote as "C") and that of French Roast coffee (denote as "F")

The first equation we create pertains to the overall weight of the coffee (20 lb total), represented by C and F as follows:

first equation    C + F = 20

Subsequently, we derive another equation regarding the mixture's cost. Each pound of City Roast costs $7.80, so for C pounds, the cost becomes $7.80 * C

For the French Roast—priced at $8.10 per pound—we deduce that F pounds will cost $8.10 * F

The total of these costs should equal the desired total for the 20 lb blend: $7.92 * 20 = $158.4

We format the total cost equation as follows:

$7.80 * C + $8.10 * F = $158.4

Next, we use the first equation to express one variable in terms of the other, allowing us to solve for "C":

C + F = 20

C = 20 - F

We then replace "C" in the second equation with this expression:

7.80 (20 - F) + 8.10 F = 158.4

7.80 * 20 - 7.80 F + 8.10 F = 158.4

Combining the F terms results in + 0.3 F

156 + 0.3 F = 158.4

Isolating F results in:

0.3 F = 158.4 - 156 = 2.4

Dividing both sides by 0.3 yields:

F = 2.4 / 0.3 = 8

This indicates that we need 8 pounds of French Roast coffee.

Consequently, the remainder (12 lb) should consist of the City Roast.

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If (a^3+27)=(a+3)(a^2+ma+9) then m equals
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Answer:

m = - 3

Step-by-step explanation:

a³ + 27 can be recognized as a sum of cubes, which factors generally as

a³ + b³ = (a + b)(a² - ab + b²). Therefore:

a³ + 27

= a³ + 3³

= (a + 3)(a² - 3a + 9).

By comparing a² - 3a + 9 to a² + ma + 9, we find that

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1 month ago
At a recent county fair, you observed that at one stand people's weight was forecasted, and were surprised by the accuracy (with
Leona [12618]

Answer:

a) Slope: \hat \beta_1 =\frac{7625.9}{1248.9}=6.106

Intercept: \hat \beta_o = 157.955 -6.106 (69.686)=-267.548

b) r=\frac{7625.9}{\sqrt{[1248.9][94228.8]}}=0.657

Additionally, the coefficient of determination is r^2 = 0.657^2 =0.432

Step-by-step explanation:

Definitions and data provided

The correlation coefficient is a measure that quantifies the strength of the relationship between two variable movements, denoted as r and ranging between -1 and 1.

The sum of squares refers to the total of the squared deviations, where deviation is defined as the difference between each value and the grand mean.

When performing multiple regression, the aim is to analyze the relationship between multiple independent variables and one dependent variable.

n=110, \sum x_i y_i = \sum (X-\bar X)(Y-\bar Y) =7625.9,\sum x^2_i=\sum (x-\bar x)^2 =1248.9, sum y^2_i=\sum(y-\bar y)^2 =94228.8

\sum Y_i =17375, \sum X_i = 7665.5

Part a

The slope can be calculated using this formula:

\hat \beta_1 =\frac{\sum (x-\bar x) (y-\bar y)}{\sum (x-\bar x )^2}

Following the substitutions, we have:

\hat \beta_1 =\frac{7625.9}{1248.9}=6.106

The intercept can be determined with this formula:

\hat \beta_o = \bar y -\hat \beta_1 \bar x

Average values for x and y can be calculated this way:

\bar X=7665.5/110 =69.686, \bar y= 17375/110=157.955

Replacing yields:

\hat \beta_o = 157.955 -6.106 (69.686)=-267.548

Part b

The correlation coefficient can be calculated using the following formula:

r=\frac{\sum (x-\bar x)(y-\bar y) }{\sqrt{[\sum (x-\bar x)^2][\sum(y-\bar y)^2]}}

In our situation:

n=110, \sum x_i y_i = \sum (X-\bar X)(Y-\bar Y) =7625.9,\sum x^2_i=\sum (x-\bar x)^2 =1248.9, sum y^2_i=\sum(y-\bar y)^2 =94228.8

We can compute the correlation coefficient by substituting values:

r=\frac{7625.9}{\sqrt{[1248.9][94228.8]}}=0.657

The coefficient of determination is r^2 = 0.657^2 =0.432

6 0
1 month ago
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