a.Write a Python function sum_1k(M) that returns the sumí‘ í‘ = âˆ‘1í‘˜í‘˜í‘€í‘€í‘˜í‘˜=1b.Compute s for M = 3 by hand and write

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a.Write a Python function sum_1k(M) that returns the sumí‘ í‘ = âˆ‘1í‘˜í‘˜í‘€í‘€í‘˜í‘˜=1b.Compute s for M = 3 by hand and write

another function test_sum_1k() that calls sum_1k(3) and checks that the answer is correct. When you call the sum_1k(3) function, you will see some messages according to if the test is successful or not.

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1 answer:

8_murik_8 [964] · Answer 1 · 2026-04-08T09:00:01+03:00

def sum_1k(M): s = 0 for k in range(1, M+1): s = s + 1.0/k return s def test_sum_1k(): expected_value = 1.0+1.0/2+1.0/3 computed_value = sum_1k(3) if expected_value == computed_value: print("Test is successful") else: print("Test is NOT successful") test_sum_1k() It appears that the hidden portion involves summing (sigma) from 1 to M with the term 1/k. Accordingly, within sum_1k(M), one should iterate from 1 to M to compute and return the sum of the expression. The test_sum_1k() function calculates the expected_value, an accurate hand-calculated value, while computed_value denotes the result of sum_1k(3). The values are then compared and an appropriate message is printed. Finally, invoke test_sum_1k() to observe the result.