Response:
#code (count_seq.py)
def count_seq():
n='2'
while True:
yield int(n)
next_value=''
while len(n)>0:
first=n[0]
count=0
while len(n)>0 and n[0]==first:
count+=1
n=n[1:]
next_value+='{}{}'.format(count,first)
n=next_value
if __name__ == '__main__':
gen=count_seq()
for i in range(10):
print(next(gen))
Clarification:
- Begin with the number 2. Utilize a string for easier manipulation rather than integers.
- Engage in an infinite loop.
- Yield the current integer value of n.
- Continue looping until n becomes an empty string.
- Repeat as long as n has content and the first digit matches the leading digit.
- Concatenate the count and the first digit to form next_value.
The question is incomplete, as it lacks a diagram of the topology and Router R1's table. I assume the user has access to both the topology and routing information.
The configuration below will assist in resolving the ACL issue:
Hosts within the 172.16.0.0/16 network should have unrestricted access to Server1, Server2, and Server3, which is currently not the case since L1 is unable to connect to Server2 or Server3.
The suggested configuration on Cisco Router R1 will rectify the ACL issues.
Answer:
Explanation:
public class Team {
private String teamName;
private int teamWins;
private int teamLosses;
public String getTeamName() {
return teamName;
}
public void setTeamName(String teamName) {
this.teamName = teamName;
}
public int getTeamWins() {
return teamWins;
}
public void setTeamWins(int teamWins) {
this.teamWins = teamWins;
}
public int getTeamLosses() {
return teamLosses;
}
public void setTeamLosses(int teamLosses) {
this.teamLosses = teamLosses;
}
public double getWinPercentage() {
return teamWins / (double) (teamWins + teamLosses);
}
}
num_cents = 109 if num_cents >= 100: print('Dollar or more') else: print('not a dollar')
