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saul85
2 months ago
13

A study is conducted in which people were asked whether they agreed or disagreed with the statement that there is only one true

love for each person. The table below gives a two-way table showing the answers to this question as well as the education level of the respondents. A person’s education is categorized as HS (high school degree or less), Some (some college), or College (college graduate or higher). Is the level of a person’s education related to how the person feels about one true love? If there is a significant association between these two variables, describe how they are related.
HS Some College Total
Agree 361 161 197 719
Disagree 558 470 786 1814
Don't know 18 26 30 74
Total 937 657 1013 2607

Calculate Chi-square statistic.
Mathematics
1 answer:
Svet_ta [12.7K]2 months ago
4 0
Refer to the explanation. A study analyzed responses to whether individuals believed there is a singular true love per person, alongside the education levels of the respondents categorized as HS (high school and below), Some (some college), or College (college grad and above). Is there a notable link between education level and belief about one true love? If an association is found, describe its nature.
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Which function has an inverse that is also a function?
Leona [12618]
An inverse function will also qualify as a function if the original is a One-to-One function. This means that each y value corresponds to exactly one x value, thus ensuring that the inverse remains a function.

The function shown in option C meets this criteria, as all x values and y values are distinct. Therefore, the inverse of the function in option C will also be a functional relation.

In contrast, other options have repeated y values, indicating they do not exhibit the one-to-one characteristic.

Hence, the correct answer is option C
3 0
2 months ago
Read 2 more answers
A rectangular schoolyard is to be fenced in using the wall of the school for one side and 150
lawyer [12517]

Answer:

Part 1) The equation is A(x)=150x-2x^2

Part 2) When x=40 m, the area of the schoolyard is A=2,800 m^2

Part 3) The valid domain consists of all real numbers exceeding zero and below 75 meters

Step-by-step explanation:

Part 1) Formulate an expression for A(x)

Let

x -----> the length of the rectangular school yard

y ---> the width of the rectangular school yard

It is known that

The perimeter for the fencing (taking the school wall as one side) is

P=2x+y

P=150\ m

thus

150=2x+y

y=150-2x -----> this is equation A

The area of the rectangular school yard is

A=xy ----> this is equation B

Substituting equation A into equation B yields

A=x(150-2x)

A=150x-2x^2

Change to function notation

A(x)=150x-2x^2

Part 2) What is the area when x=40?

With x equal to 40 m

substitute the value into the expression from Part 1 to determine A

A(40)=150(40)-2(40^2)

A(40)=2,800\ m^2    

Part 3) What would be a suitable domain for A(x) in this scenario?

We understand that

A signifies the area of the rectangular school yard

x characterizes the length of the rectangular school yard

It follows that

A(x)=150x-2x^2

This forms a vertical parabola opening downwards

The vertex indicates a maximum point

The x-coordinate of the vertex corresponds to the length that maximizes the area

The y-coordinate of the vertex denotes the maximum area

The vertex corresponds to (37.5, 2812.5)

Refer to the accompanying figure

Consequently,

The peak area achieved is 2,812.5 m^2

The x-intercepts are located at x=0 m and x=75 m

The domain for A is the range -----> (0, 75)

All real numbers greater than zero and less than 75 meters

5 0
3 months ago
Construct an interval estimate for the given parameter using the given sample statistic and margin of error. For μ1-μ2, using x¯
zzz [12365]

Answer: CI = (0, 8)

Step-by-step explanation: The confidence interval for the difference in means is given as

Lower limit

= (x1 - x2) + margin of error

Upper limit

= (x1 - x2) - margin of error

Where x1 - x2 = 8 and the margin of error = 8

For the lower limit,

= 8 - 8 = 0

For the upper limit

= 8 + 8 = 16

Thus, CI = (0, 8)

4 0
3 months ago
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