The solution to this inequality is.5>x 
A disadvantage of the contention approach for LANs, such as CSMA/CD, is the capacity wasted due to multiple stations attempting
1 answer:
Response:
The problem is summarized in the following explanation segment.
Detailed explanation:
The estimate of the slots or positions lost due to simultaneous transmission attempts can be calculated as follows:
Evaluating the likelihood of transmitting gives us "p".
When considering two or more attempts, we arrive at
Fraction of slots wasted,
=
Substituting the values yields
=
=
Thus, the answer appears to be correct.
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Answer:
The value calculated is Z = 2.53, which exceeds 1.96 at a significance level of 0.05
This leads to the rejection of the null hypothesis H₀
Thus, we accept the alternative hypothesis
This implies that individuals participating in Weight Reducers will lose more than 10 pounds
Step-by-step explanation:
Step(i):-
The size of the random sample 'n' = 50
The new weight-loss program, Weight Reducers International, claims that members will shed an average of 10 pounds within the initial two weeks, with a standard deviation of 2.8 pounds.
Population mean 'μ' = 10 pounds
Population standard deviation 'σ' = 2.8 pounds
Sample mean 'x⁻' = 9
Significance level ∝ = 0.05
Step(ii):-
Null hypothesis: H₀: μ < 10
Alternative hypothesis: H₁: μ > 10
Test statistic calculation
The determined Z value is 2.53
In this case, the critical value Z is 1.96 at the 0.05 significance level
Step(iii):-
Calculated Z value of 2.53 is greater than 1.96 at a significance level of 0.05
Consequently, we reject the null hypothesis H₀
We accept the alternative hypothesis
Conclusion:-
We determine that individuals who sign up for Weight Reducers will experience a weight loss exceeding 10 pounds
Answer:
Part 1) The equation is
Part 2) When x=40 m, the area of the schoolyard is A=2,800 m^2
Part 3) The valid domain consists of all real numbers exceeding zero and below 75 meters
Step-by-step explanation:
Part 1) Formulate an expression for A(x)
Let
x -----> the length of the rectangular school yard
y ---> the width of the rectangular school yard
It is known that
The perimeter for the fencing (taking the school wall as one side) is
thus
-----> this is equation A
The area of the rectangular school yard is
----> this is equation B
Substituting equation A into equation B yields
Change to function notation
Part 2) What is the area when x=40?
With x equal to 40 m
substitute the value into the expression from Part 1 to determine A
Part 3) What would be a suitable domain for A(x) in this scenario?
We understand that
A signifies the area of the rectangular school yard
x characterizes the length of the rectangular school yard
It follows that
This forms a vertical parabola opening downwards
The vertex indicates a maximum point
The x-coordinate of the vertex corresponds to the length that maximizes the area
The y-coordinate of the vertex denotes the maximum area
The vertex corresponds to (37.5, 2812.5)
Refer to the accompanying figure
Consequently,
The peak area achieved is 2,812.5 m^2
The x-intercepts are located at x=0 m and x=75 m
The domain for A is the range -----> (0, 75)
All real numbers greater than zero and less than 75 meters
