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ZanzabumX
10 days ago
15

Suppose that a Coke/Pepsi survey was conducted of 40 randomly selected individuals from Gainesville. Thirty people selected Coke

. Which of the following statements correctly describes how the confidence interval for the population proportion of people that prefer Coke should be computed?
a. There are not 15 successes and 15 failures. A confidence interval can not be done.
b. There are not 15 successes and 15 failures. A confidence interval can be computed by adding 2 successes and 2 failures.
c. There are not 15 successes and 15 failures. A confidence interval can be computed by adding 4 successes and 5 failures.
d. There are at least 15 successes and 15 failures. A large sample confidence interval for the population proportion can be computed with no additional value.
Mathematics
1 answer:
babunello [11.8K]10 days ago
4 0

Answer:yo

Step-by-step explanation:yo

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An oblique prism has trapezoidal bases and a vertical height of 10 units. An oblique trapezoidal prism is shown. The trapezoid h
Svet_ta [12734]

Response:

Volume of the trapezoidal prism = 15x^2 cubic units

Detailed explanation:

First, let’s calculate the area of the trapezoidal bases.

The lengths of the parallel sides are x and 2x, averaging to 1.5x.

The height stands at x

Consequently, area of the trapezoidal base comes out to be 1.5x * x = 1.5x^2

The volume of this prism is computed as area of the base multiplied by height

(the length is not a factor, but height certainly is)

Thus, 1.5x^2 * 10 yields 15x^2

5 0
27 days ago
15 points!!!
PIT_PIT [12445]
8+292=300

8 out of 300 were defective.

\frac{8}{300}=\frac{x}{3000} \\ \\ 8*3000=300*x \\ \\ 24000=300x \\ \\ 80=x

That corresponds to 80 pairs being defective
4 0
20 days ago
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One student from a high school will be selected at random. Let A be the event that the selected student is a student athlete, an
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0.32

Step-by-step explanation:

P(B|A) = P(A∩B) / P(A)

0.25 = 0.08 / P(A)

P(A) = 0.32

8 0
1 month ago
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While driving from his home to his workplace, Chris has to pass through two traffic lights. The general probability of getting a
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These occurrences are unlikely to take place!

I hope this is helpful
6 0
1 month ago
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Tim was given a large bag of sweets and ate one third of the sweets before stopping as he was feeling sick. The next day he ate
Leona [12618]

Answer: Initially, he had 27 sweets.

Step-by-step explanation: The most logical approach is to work backwards from what remained after the third day to the start of the first day.

On the third day, he consumed one-third of his sweets and was left with 8. If we let the total sweets on day three be denoted as a, then one-third of a equals what he ate and the two-thirds left equals 8, giving us:

8/a = 2/3

By cross-multiplying, we find:

8 x 3 = 2a

Therefore, 24 = 2a

This leads to a = 12.

Let the sweets on day two be represented as b. If he consumed one-third of b and was left with 12, we have the same structure; hence:

12/b = 2/3

Cross-multiplying gives:

12 x 3 = 2b

So, 36 = 2b, leading to b = 18.

Denote the number of sweets on day one as x. If one-third of x was eaten and 18 remained, we can set up the equation:

18/x = 2/3

Again, cross-multiplying results in:

18 x 3 = 2x

Which simplifies to 54 = 2x, yielding x = 27.

Thus, Tim received 27 sweets at the start.

3 0
1 month ago
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