Set t = 0 to find the initial height
Answer:
Step-by-step explanation:
The prices he received quotes for are as follows: $663, $273, $410, $622, $174, $374
To begin, we will find the average.
Average = total of data points/ number of data points.
Total of data points =
663 + 273 + 410 + 622 + 174 + 374
= 2516
Total count = 6
Average = 2516/6 = 419.33
Standard deviation = √summation(x - m)^2/n
summation(x - m)^2/n = (663 - 419.33)^2 + (273 - 419.33)^2 + (410 - 419.33)^2 + (622 - 419.33)^2 + (174 - 419.33)^2 + (374 - 419.33)^2
= 179417.9334/6 = 29902.9889
Standard deviation = √29902.9889
= 172.9
No. Allocate 2/3 of the space to Grano and 1/3 to Wheatie. This results in approximately 57% for Wheatie and 43% for Grano—meaning 60(.57)=34.2 ft² for Wheatie and 60(.43)=25.8 ft² for Grano. Therefore, there would be about 85.5 boxes of Wheatie and 129 boxes of Grano, leading to a total profit of 129(1)+85(1.35)=$243.75. The best choice would be to place 200 boxes of Grano and 50 boxes of Wheaties on the shelf. Allocating 40 ft² to Granos (200(.2)) and 20 ft² to Wheaties (50(.4)) means that 40/60=2/3=66.6% of the space would be for Granos, and 20/60=1/3=33.3% would be for Wheaties. The total profit would be 200(1)+50(1.35)=$267.5.
Question 1: (2.2, -1.4). Question 2: (1.33, 1). Providing a detailed analysis, the equations for the given lines are specified as (1) passing through points (0, 2.5) and (2.2, 1.4), and (2) through (0, -3) and (2.2, -1.4). We are tasked with locating a common solution or intersection of these equations. This leads to finding x = 2.2, and consequently y = -1.4. Therefore, the solution set is (2.2, -1.4). For question 2, the equations yield a solution of (1.33, 1).
Start by letting x represent the number of Sam's pencils. Then Sari has 3x (since she has three times as many)
Together they total 28 pencils:
x + 3x = 28
4x = 28 /:4 (divide both sides by 4)
x = 7
So Sam has 7 pencils.
Sari, having three times as many, has 7 * 3 = 21.[[TAG_8]]
